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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 7: Q. 68 (page 504)

In Problems 64-75, solve each equation on the interval $0 鈮� 胃 < 2 蟺$

Short Answer

Expert verified

The solution set is $胃鈭� \{\frac{蟺}{3}, \frac{2 蟺}{3}, \frac{4 蟺}{3}, \frac{5 蟺}{3}\}$

Step by step solution

01

Given information

Given equation $\sec^{2} 胃 = 4$

02

Checking the value lie in the specific interval

Calculating, we get

$\sec^{2} 胃 = 4 s e c 胃 = 卤 2 \frac{1}{\cos 胃} = 2 \frac{1}{\cos 胃} = - 2 \cos (\frac{蟺}{3}) = \cos (\frac{5 蟺}{3}) = \frac{1}{2} \cos (\frac{2 蟺}{3}) = \cos (\frac{4 蟺}{3}) = - \frac{1}{2}$

The solution set is $胃鈭� \{\frac{蟺}{3}, \frac{2 蟺}{3}, \frac{4 蟺}{3}, \frac{5 蟺}{3}\}$

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Most popular questions from this chapter

If $x = 2 \tan 胃$ , express $\cos (2 胃)$ as a function ofx.

Establish each identity.

$\tan 胃 + c o t 胃 = s e c 胃 c s c 胃$

In Problems 9鈥�36, find the exact value of each expression.

$\sec (\cos^{- 1} \frac{1}{2})$

if $\sin 伪 = - \frac{4}{5}$ , $蟺 < 伪 < \frac{3 蟺}{2}$ , then $\cos 伪 =$ _____

Multiply: $\frac{\sin (胃)}{1 + \cos (胃)} \frac{1 - \cos (胃)}{1 - \cos (胃)}$

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