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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 7: Q. 5 (page 485)

$\cos (伪 + 尾) = \cos 伪 \cos 尾_______\sin 伪 \sin 尾$

Short Answer

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Step by step solution

01

Step 1. Given information

We need to fill the blank in the given expression with the right sign,

$\cos (伪 + 尾) = \cos 伪 \cos 尾_______\sin 伪 \sin 尾$

02

Step 2. Fill the blank

The compound angle $\cos (伪 + 尾)$ formula is:

$\cos (伪 + 尾) = \cos 伪 \cos 尾 - \sin 伪 \sin 尾$

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Most popular questions from this chapter

Establish each identity.

${(2 a \sin 胃 \cos 胃)}^{2} + a^{2} {(\cos^{2} 胃 - \sin^{2} 胃)}^{2} = a^{2}$

Rewrite over a common denominator:

$\frac{\sin (胃) + \cos (胃)}{\cos (胃)} + \frac{\sin (胃) + \cos (胃)}{\sin (胃)}$

Multiply: $\frac{\cos (胃)}{1 - \sin (胃)} \frac{1 + \sin (胃)}{1 + \sin (胃)}$

Establish each identity.

$\tan 胃 + c o t 胃 = s e c 胃 c s c 胃$

Find the value of the number C:

$\frac{1}{2} \sin^{2} x + C = - \frac{1}{4} \cos (2 x)$

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