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91Ó°ÊÓ

if sinθ=13, is in quadrant 2 find exact value of

a)cosθb)sin(θ+π6)c)cos(θ-π3)d)tan(θ+π4)

Short Answer

Expert verified

The values are

a)cosθ=-223b)sin(θ+π6)=3-226c)cos(θ-π3)=3-226d)tan(θ+π4)=-1+2222+1

Step by step solution

01

Given information

We are givensinθ=13

02

Find cosθ

We have,

cosθ=1-sin2θcosθ=1-19cosθ=-223asθisin2ndquadrant

03

Find sin(θ+π6)

We have,

sin(θ+π6)=sinθcosπ6+sinπ6cosθsin(θ+π6)=13(32)+(-223)(12)sin(θ+π6)=3-226

04

Find cos(θ+π3)

We have,

cos(θ-π3)=cos(θ)cos(π3)+sin(θ)sin(π3)cos(θ-π3)=(-223)12+13(32)cos(θ-π3)=3-226

05

Find tan(θ+π4)

We have,

tan(θ+π4)=tan(θ)+tan(π4)1-tan(θ)tan(π4)tan(θ+π4)=-122+11-(-122)tan(θ+π4)=-1+2222+1

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