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Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 7: Q. 3 (page 485)

(a) $\sin \frac{蟺}{4} 路 \cos \frac{蟺}{3} =$
(b) $\tan \frac{蟺}{4} - \sin \frac{蟺}{6} =__$

Short Answer

Expert verified

(a) $\sin \frac{蟺}{4} 路 \cos \frac{蟺}{3} = \frac{1}{2 \sqrt{2}}$

(b)localid="1646824125334" $\tan \frac{蟺}{4} - \sin \frac{蟺}{6} = \frac{1}{2}$

Step by step solution

01

Part (a) Step 1. Find the value

We know,

$\sin \frac{蟺}{4} = \frac{1}{\sqrt{2}} \cos \frac{蟺}{3} = \frac{1}{2}$

Therefore,

$\sin \frac{蟺}{4} 路 \cos \frac{蟺}{3} = \frac{1}{\sqrt{2}} 路 \frac{1}{2} \sin \frac{蟺}{4} 路 \cos \frac{蟺}{3} = \frac{1}{2 \sqrt{2}}$

02

Part (b) Step 1. Find the value

We know,

$\tan \frac{蟺}{4} = 1 \sin \frac{蟺}{6} = \frac{1}{2}$

Therefore,

localid="1646824093386" $\tan \frac{蟺}{4} - \sin \frac{蟺}{6} = 1 - \frac{1}{2} \tan \frac{蟺}{4} - \sin \frac{蟺}{6} = \frac{1}{2}$

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