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In Problems 11–34, solve each equation on the interval 0≤θ≤2π.

sec3θ2=-2

Short Answer

Expert verified

The solution set is4Ï€9,8Ï€9,16Ï€9.

Step by step solution

01

Step 1. Given Information 

In the given problem we have to solve each equation on the interval 0≤θ≤2π.

sec3θ2=-2

02

Step 2. In the interval [0,2π), the sine function equals -2 at 2π3

So, we know that 3θ2must equal 2π3.

To find these solutions, write the general formula that gives all the solutions.

role="math" localid="1646590784861" 3θ2=2Ï€3+2Ï€²Ô

Multiply with 23on both side

role="math" localid="1646591123910" 3θ2·23=232Ï€3+2Ï€²Ôθ=23·2Ï€3+23·2Ï€²Ôθ=4Ï€9+4Ï€²Ô3

θ=8Ï€9+4Ï€²Ô3

03

Step 3. The general formula is θ=4π9+4πn3,θ=8π9+4πn3

So the value of given function in interval [0,2Ï€)is

role="math" localid="1646591235840" θ=4π9+4π×03θ=4π9+4π×13θ=8π9+4π×03θ=4π9θ=4π9+4π3θ=8π9θ=4π9θ=4π+12π9θ=4π9θ=16π9

So the solution set is4Ï€9,8Ï€9,16Ï€9

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