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express each product as a sum containing only sines or only cosines

sinϑsin2ϑ

Short Answer

Expert verified

12[cosϑ-cos3ϑ]

Step by step solution

01

Step 1. Given expression 

sinϑsin2ϑ

02

Step 2. expressing them in terms of single sine or cosine

Using identity :

cosx-cosy=-2sin(x+y2)sin(x-y2)

We get :

sinϑsin2ϑ=12[cos(2ϑ-ϑ)-cos(2ϑ+ϑ)]sinϑsin2ϑ=12[cosϑ-cos3ϑ]

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