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Chapter 7: Q. 112 (page 468)

The index of refraction of light in passing from a vacuum into dense flint glass is 1.66. If the angle of incidence is 50掳, determine the angle of refraction.

Short Answer

Expert verified

The angle of refraction is 27.45o.

Step by step solution

01

Step 1. Given Information  

The index of refraction of light in passing from a vacuum into dense flint glass is 1.66. If the angle of incidence is 50掳.

We have to determine the angle of refraction.

02

Step 2. The Snell's law tell us that when you have two medium with refraction index n1 and n2 the equation is n1sinθ1=n2sinθ2.

With 胃1and胃2the angle in the first medium and in second medium respectively.

For us the initial angle 胃1=50oandn2=1.66.

In order to find 胃2we need to know n1.

Assumen1=1for air.

03

Step 3. Then our equation is

1路sin50o=1.66路sin胃2

Divide by 1.66 on both side

sin50o1.66=1.661.66路sin胃2sin50o1.66=sin胃2sin胃2=sin50o1.66胃2=sin-1sin50o1.66

04

Step 4. After solving the equation is θ2=sin-1sin50o1.66

胃2鈮�sin-10.7661.66胃2鈮�sin-10.461胃2鈮�27.45o

The angle of refraction is 27.45o.

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sin2胃2=______2.

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