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In Problems 11–34, solve each equation on the interval 0≤θ≤2π.

2sinθ+3=2

Short Answer

Expert verified

The solution set is7Ï€6,11Ï€6.

Step by step solution

01

Step 1. Given Information

In the given problem we have to solve each equation on the interval0≤θ≤2π.

2sinθ+3=2

02

Step 2. Firstly solving the equation 2sinθ+3=2

Subtract by 3 on both side

2sinθ+3-3=2-32sinθ=-1

Divide by 2 on both side

22sinθ=-12sinθ=-12

03

Step 3. After solving the equation sinθ=-12

In the interval [0,2π), there are two angles θfor which

localid="1646564805462" sinθ=-12:θ=7π6andθ=11π6

So the solution set is 7Ï€6,11Ï€6.

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