/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 106 Optical methods of measurement o... [FREE SOLUTION] | 91Ó°ÊÓ

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Optical methods of measurement often rely on the interference of two light waves. If two light waves, identical except for a phase lag, are mixed together, the resulting intensity, or irradiance, is given by I1=4A2(cscθ-1)(secθ+tanθ)cscθsecθ

Show that this is equivalent toI1=(2Acosθ)2

Short Answer

Expert verified

The given expressions are equivalent.

Step by step solution

01

Step 1. Given Information

The given expressions areI1=4A2(cscθ-1)(secθ+tanθ)cscθsecθandI1=(2Acosθ)2

02

Step 2. Calculation 

Consider one expression and prove it is equivalent to the other given expression.

4A2(cscθ-1)(secθ+tanθ)cscθsecθ=4A2(1sinθ-1)(1cosθ+sinθcosθ)1sinθ×1cosθ=4A21-sinθsinθ(1+sinθcosθ)1sinθcosθ=4A2(1-sinθ)(1+sinθ)sinθcosθ1sinθcosθ=4A2(1-sinθ)(1+sinθ)1=4A2(1-sin2θ)=4A2(cos2θ)=(2Acosθ)2

Thus, we can conclude that the given expressions are equivalent.

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