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A searchlight at the grand opening of a new car dealership casts a spot of light on a wall located 75 meters from the searchlight. The acceleration r of the spot of light is found to be r=1200secθ(2sec2θ-1). Show that this is equivalent tor=1200(1+sin2θcos3θ)

Short Answer

Expert verified

The given expressions are equivalent.

Step by step solution

01

Step 1. Given Information

The given expressions arer=1200secθ(2sec2θ-1)andr=1200(1+sin2θcos3θ)

02

Step 2. Calculation

Consider one expression and prove it is equivalent to the other given expression.

1200secθ(2sec2θ-1)=1200cosθ(2cos2θ-1)=1200cosθ(2-cos2θcos2θ)=1200cosθ(1+1-cos2θcos2θ)=1200cosθ(1+sin2θcos2θ)=1200cos3θ(1+sin2θ)=r

Thus, we can conclude that the given expressions are equivalent.

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