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(a) Graph f(x)=-4cosxandg(x)=2cosx+3 on the

same Cartesian plane for the interval 0,2Ï€.

(b) Solve f(x)=g(x) on the interval 0,2Ï€and label the points of intersection on the graph drawn in part (a).

(c) Solve f(x)>g(x) on the interval 0,2Ï€.

(d) Shade the region bounded by f(x)=-4cosxandg(x)=2cosx+3between the two points found in part (b) on the graph drawn in part (a).

Short Answer

Expert verified

The graph off(x)=-4cosxandg(x)=2cosx+3on the same cartesian plane for the interval0,2Ï€is

Part b. The solution of f(x)=g(x)ontheinterval0,2Ï€is 2Ï€3,4Ï€3and the points on the graph is

Part c. The solution off(x)>g(x)ontheinterval0,2Ï€is2Ï€3<x<4Ï€3.

Part d. The shaded region bounded by f(x)=-4cosxandg(x)=2cosx+3between the two points found in part (b) on the graph drawn in part (a) is

Step by step solution

01

Part (a) Step 1. Given Information 

The given functions aref(x)=-4cosxandg(x)=2cosx+3.

We have to graph the given functions on the same cartesian plane for the interval0,2Ï€.

02

Part (a)  Step 2. Sketch the graph 

The graph of f(x)=-4cosxandg(x)=2cosx+3on the same cartesian plane for the interval0,2Ï€is

03

Part (b) Step 1. Solving 

We have to solve f(x)=g(x),0≤x≤2π.

f(x)=g(x)-4cosx=2cosx+3-6cosx=3cosx=-12x=2Ï€3,4Ï€3

The points of the intersection on the graph drawn in part (a) is

04

Part (c) Step 1. Solving 

We have to solve f(x)>g(x)on the interval 0,2Ï€.

f(x)>g(x)-4cosx>2cosx+3-6cosx>3cosx>-122Ï€3<x<4Ï€3

05

Part (d) Step 1. Shading the region 

The shaded region bounded by f(x)=-4cosxandg(x)=2cosx+3between the two points found in part (b) on the graph drawn in part (a) is

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