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Semi elliptical Arch Bridge The arch of a bridge is a semi ellipse with a horizontal major axis. The span is 30feet, and the top of the arch is 10feet above the major axis. The roadway is horizontal and is 2feet above the top of the arch. Find the vertical distance from the roadway to the arch at 5-foot intervals along the roadway.

Short Answer

Expert verified

The vertical distance from the roadway to arch at 5foot intervals are2.57feet ,4.54feet and12feet.

Step by step solution

01

Step 1. Given information.

The major axis of the arch is parallel to the x-axis. since the span of the arch is 30feet, this means

a=302a=15

The top of the arch is 10feet above the major axis.This means b=10.

The road ways lies 2feet above top of the arch.Thus, the coordinates of the center are (0,-12).

02

Step 2. The equation of the ellipse and graph of the arch.

The equation of the ellipse is (x-0)2225+(y+12)2100=1

The graph of the arch is

03

Step 3. Vertical distance from roadway to arch.

Now, putting x=5in the equation of ellipse

role="math" localid="1646806151750" 25225+(y+12)2100=1(y+12)2=8009y=±2023-12y=-2.57,-21.42

We have considered only the upper semi- ellipse constituting the arch.

Putting x=10in the equation we get.

role="math" localid="1646806607812" 100225+(y+12)2100=1(y+12)2=5009y=±1053-12y=-4.54

For x=-15and x=15y=-12

Thus, the vertical distances from the roadway to arch at5foot intervals are2.57feet,4.54feetand12feet.

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