/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 44 Find the vertex, focus, and dire... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Q. 44 (page 644)

Find the vertex, focus, and directrix of each parabola. Graph the equation by hand. Verify your graph using a graphing utility.

y+12=-4x-2

Short Answer

Expert verified

The vertex is 2,-1,focus is 1,-1and directrix is x=3.

Step by step solution

01

Step 1. Given information .

Consider the given equationy+12=-4x-2.

02

Step 2. Analyze the equation .

The standard form of parabola is y-k2=4ax-h

Compare the given equation with standard form.

y-k2=4ax-hy+12=-4x-24a=-4a=-1h=2,k=-1

Further simplify.

Since the value of a=-1then the vertex ish,k=2,-1and focus ish+a,k=1,-1and the directrix isx=h-a=3

03

Step 3. Plot the graph .

The graph of the equation by using graphing utility just shown below.

Here V is the vertex , F is the focus and line x=3represents directrix of the parabola .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Problems 43鈥�52, identify the graph of each equation without applying a rotation of axes.

10x2-12xy+4y2-x-y-10=0

A hyperbola for which a=bis called an equilateral hyperbola. Find the eccentricity eof an equilateral hyperbola.

[Note: The eccentricity of a hyperbola is defined in Problem 81.]

The graph of a parabola is given. Match graph to its equation.

and equations are,

A)y2=4xC)y2=-4xE)(y-1)2=4(x-1)G)(y-1)2=-4(x-1)B)x2=4yD)x2=-4yF)(x+1)2=4(y+1)H)(x+1)2=4(y+1)

If (x,y)are the rectangular coordinates of a point P and (r,胃)are its polar coordinate, thenx=_______andy=______.

The distance dfrom P1=(2,-5)to P2=(4,-2)is d=________.
See all solutions

Recommended explanations on Math Textbooks

Logic and Functions

Read Explanation

Decision Maths

Read Explanation

Discrete Mathematics

Read Explanation

Probability and Statistics

Read Explanation

Statistics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.