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In Problems 13–24, analyze each equation and graph it

r=82+4cosθ

Short Answer

Expert verified

The given represents a hyperbola.

Step by step solution

01

Step 1. Given Information 

We are given an equation

r=82+4cosθ

We need to find the graph of the equation.

02

Step 2. Analyze the equation 

Compare the given equation with r=ep1+ecosθ

The given equation becomes,

r=82+4cosθ·1212r=41+2cosθ

Therefore,

e=2ep=4⇒(2)p=4⇒p=42=2

Since e>1, therefore it is a hyperbola.

03

Step 3. Plotting points 

Now, we will calculate the points from the given equation,

θ=0:r=82+4cos(0)=82+4=86=4343,0θ=π2:r=82+4cosπ2=82+0=82=44,π2θ=π:r=82+4cos(π)=82-4=8-2=-4(-4,π)θ=3π2:r=82+4cos3π2=82+0=82=4

04

Step 4. Required graph

Plotting the points, we get the graph as,

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