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In Problems 13–24, analyze each equation and graph it

r=124+8sinθ

Short Answer

Expert verified

The equation represents a hyperbola.

Step by step solution

01

Step 1. Given Information 

We are given an equation

r=124+8sinθ

We need to find the graph of the equation.

02

Step 2. Analyze the equation 

Compare the given equation with r=ep1+esinθ

The given equation becomes,

r=124+8sinθ·1414r=31+2sinθTherefore,e=2ep=3⇒(2)p=3⇒p=32Since,e>1

Therefore, a hyperbola will be formed.

03

Step 3. Plotting points 

Now, we will calculate the points from the given equation,

θ=0:r=124+8sin(0)=124+0=124=3θ=π2:r=124+8sinπ2=124+8=1212=1θ=π:r=124+8sin(π)=124+0=124=3θ=3π2:r=124+3sin3π2=124-8=12-4=-3-3,3π2

04

Step 4. Required graph 

Plotting the points, we get the graph as,

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