/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 40 In Problems 33鈥� 44, find the o... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 14: Q. 40 (page 889)

In Problems 33鈥� 44, find the one-sided limit.

limx鈫�1-x3-xx-1

Short Answer

Expert verified

limx鈫�1-x3-xx-1=2the solution

Step by step solution

01

step 1.introduction

given limits
limx鈫�1-x3-xx-1

02

step 2.simplification of equation

given equation

=x3-xx-1=x(x2-1)x-1=x(x+1)(x-1)x-1=x(x+1)

03

step 3.the solution

the limit value the

limx鈫�1-x3-xx-1=lim(x(x+1))x鈫�1-=(1(1+1))=2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Problem, graph each function. Use the graph to find the indicated limit, if it exists.

limx鈫�2f(x),f(x)=x2ifx鈮�22x-1ifx>2

Use the graph shown to determine if the limit exists. If it does, find its value.

In Problems 7鈥� 42, find each limit algebraically.

limx鈫�1x2+13

In Problems 7鈥� 42, find each limit algebraically.

limx鈫�23x+4x2+x.

In Problems 13鈥�32, use the accompanying graph of y = f(x).

Findlimx鈫�-4+f(x).
See all solutions

Recommended explanations on Math Textbooks

Pure Maths

Read Explanation

Decision Maths

Read Explanation

Mechanics Maths

Read Explanation

Geometry

Read Explanation

Calculus

Read Explanation

Applied Mathematics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.