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In Problems 7– 42, find each limit algebraically.

limx→1x3-x2+x-1x4-x3+2x-2.

Short Answer

Expert verified

The answer is23.

Step by step solution

01

Step. 1 Given Information

Firstly, we check whether the given function is in indeterminant form or not.

​f(x)=x3-x2+x-1x4-x3+2x-2

Put x=1in the numerator we get,

x3-x2+x-1=1-1+1-1=0

Put x=1in the denominator we get,

x4-x3+2x-2=1-1+2-2=0.

Since both numerator and denominator gives 0 means they both have x=1as their common root.

02

Step. 2 Factorizing

Denominator,x4-x3+2x-2=x3(x-1)+2(x-1)=(x3+2)(x-1).

Numerator ,x3-x2+x-1=x2(x-1)+1(x-1)=(x2+1)(x-1).

So,

limx→1x3-x2+x-1x4-x3+2x-2=limx→1(x2+1)(x-1)(x3+2)(x-1)=limx→1(x2+1)(x3+2).

Now we can put the limit directly.

03

Step. 3 Final calculation of the limit

limx→1x2+1x3+2=1+11+2=23.

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