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In Problems 21–32, find the derivative of each function at the given number.

f(x)=x3-2x2+xat-1

Short Answer

Expert verified

The derivative of the given function at -1is equal to8

Step by step solution

01

Step 1. Given information

Given function is f(x)=x3-2x2+x

We have to find the derivative of the given function at-1

02

Step 2. Definition of the derivative

Let's say a function

The derivative of the function at is defined as

f'(c)=limx→cf(x)-f(c)x-c

03

Step 3. Finding the derivative

By substituting the given function in the derivative definition,

we will get:

f'(-1)=limx→-1f(x)-f(-1)x-(-1)⇒f'(-1)=limx→-1(x3-2x2+x)-((-1)3-2(-1)2-1)x+1⇒f'(-1)=limx→-1(x3-2x2+x)+4x+1

04

Step 4. Simplifying the limit

By rewriting the limit, we will have:

f'(-1)=limx→-1x3-2x2+x+4x+1⇒f'(-1)=limx→-1(x+1)(x2-3x+4)x+1⇒f'(-1)=limx→-1(x2-3x+4)⇒f'(-1)=(-1)2-3(-1)+4⇒f'(-1)=8

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