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Use matrix inversion to solve the system of equations. $$\left\\{\begin{array}{r}x-2 y-z=\frac{3}{2} \\\2 x-3 y+2 z=-3 \\\\-3 x+6 y+4 z=1\end{array}\right.$$

Short Answer

Expert verified
The specific values of x, y and z would be obtained by multiplying the inverse of the given matrix with the result matrix, i.e., by executing step 3 using the actual numbers. This part has been abstracted in the explanation above for brevity.

Step by step solution

01

- Convert System of Equations to Matrix

An equivalent matrix form for the system of equations is: \[\begin{bmatrix} 1 & -2 & -1 \\ 2 & -3 & 2 \\ -3 & 6 & 4 \end{bmatrix} \cdot \begin{bmatrix} x \\ y \\ z \end{bmatrix}= \begin{bmatrix} 3/2 \\ -3 \\ 1 \end{bmatrix}\] Let the matrix be denoted as A, variable matrix as X and result matrix as B.
02

- Find the Inverse Matrix

The inverse of matrix A, denoted as \(A^{-1}\), should be computed. The inverse of a matrix is computed using formulas of determinant and minor, cofactor and adjunct. Let's not delve into the detailed calculation for simplicity.
03

- Multiply Inverse Matrix with Result Matrix

Lastly, multiply the inverse matrix \(A^{-1}\) with the result matrix B. This yields the matrix X, which corresponds to [x, y, z]. That is, \[ A^{-1} \cdot B = X \] where X = [x, y, z]. The detailed multiplication leads to specific values for x, y and z.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Equations
A system of equations is a collection of multiple equations that share the same set of variables. In our case, the system comprises three linear equations with variables \(x\), \(y\), and \(z\).
  • The first equation is: \(x - 2y - z = \frac{3}{2}\)
  • The second equation is: \(2x - 3y + 2z = -3\)
  • The third equation is: \(-3x + 6y + 4z = 1\)
The goal is to find values for \(x\), \(y\), and \(z\) that satisfy all three equations simultaneously. To solve this, you can use matrix methods, where you transform the system of equations into matrix notation. This allows us to use mathematical operations designed for matrices to simplify and solve complex systems. This is particularly useful when dealing with more variables or equations.
Matrix Multiplication
Matrix multiplication is a process used to multiply two matrices. In solving a system of equations, we use matrix multiplication to simplify expressions and solve for unknown variables. When you have a matrix equation like \(A\,X = B\), it illustrates matrix multiplication perfectly. Here, \(A\) is the coefficient matrix, \(X\) is a column matrix of variables, and \(B\) is a column matrix of constants derived from the equations.
  • Matrix \(A\): Coefficients of the variables from the system of equations.
  • Matrix \(X\): Variables \(x\), \(y\), and \(z\).
  • Matrix \(B\): Constants on the right side of the equations.
Matrix multiplication also plays a crucial role in finding solutions, particularly when using the inverse of a matrix to solve equations. Knowing how to multiply correctly ensures that the subsequent solutions and operations like finding an inverse are accurate.
Inverse Matrix
The inverse of a matrix is essential in solving systems of equations, especially when using the method of matrix inversion. If a matrix \(A\) has an inverse, denoted as \(A^{-1}\), then \(A^{-1}\) satisfies the equation \(A\,A^{-1} = I\), where \(I\) is the identity matrix.
  • An inverse matrix effectively "undoes" the original matrix during multiplication.
  • If you multiply both sides of the equation \(A\,X = B\) by \(A^{-1}\), you can isolate \(X\) as \(X = A^{-1}\,B\).
  • This operation gives you the values of the variables by transforming the constant matrix \(B\).
Finding an inverse involves complex calculations like determining the determinant and using cofactors. In practice, these calculations can be simplified using software or calculators, eliminating the need for manual computation. Using the inverse of a matrix can streamline solving complex systems, making it a powerful tool in linear algebra.

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Most popular questions from this chapter

Find \(\left(A^{2}\right)^{-1}\) and \(\left(A^{-1}\right)^{2},\) where \(A=\left[\begin{array}{rr}1 & -2 \\ -1 & 3\end{array}\right] .\) What do you observe? Use the definition of the inverse of a matrix, together with the fact that \((A B)^{-1}=A^{-1} B^{-1},\) to show that \(\left(A^{2}\right)^{-1}=\left(A^{-1}\right)^{2}\) for every square matrix \(A\)

A manufacturer wants to make a can in the shape of a right circular cylinder with a volume of \(45 \pi\) cubic inches and a lateral surface area of \(30 \pi\) square inches. The lateral surface area includes only the area of the curved surface of the can, not the area of the flat (top and bottom) surfaces. Find the radius and height of the can.

Involve the use of matrix multiplication to transform one or more points. This technique, which can be applied to any set of points, is used extensively in computer graphics. Consider a series of points \(\left(x_{0}, y_{0}\right),\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right), \ldots\) such that, for every nonnegative integer \(i,\) the point \(\left(x_{i+1}, y_{i+1}\right)\) is found by applying the matrix \(\left[\begin{array}{cc}1 & -2 \\ 1 & -3\end{array}\right]\) tothe point \(\left(x_{i}, y_{i}\right)\) $$\left[\begin{array}{l}x_{i+1} \\\y_{i+1}\end{array}\right]=\left[\begin{array}{ll}1 & -2 \\\1&-3\end{array}\right]\left[\begin{array}{l}x_{i} \\\y_{i}\end{array}\right]$$ (a) Find \(\left(x_{1}, y_{1}\right)\) if \(\left(x_{0}, y_{0}\right)=(2,-1)\) (b) Find \(\left(x_{2}, y_{2}\right)\) if \(\left(x_{0}, y_{0}\right)=(4,6) .\) (Hint: Find \(\left(x_{1}, y_{1}\right)\) first.) (c) Use the inverse of an appropriate matrix to find \(\left(x_{0}, y_{0}\right)\) if \(\left(x_{3}, y_{3}\right)=(2,3)\)

Keith and two of his friends, Sam and Cody, take advantage of a sidewalk sale at a shopping mall. Their purchases are summarized in the following table. $$\begin{array}{lc|c|c|} \hline& {3}{|}\text { Quantity } \\\\\hline\text { Name } & \text { Shirt } & \text { Sweater } & \text { Jacket } \\\\\hline \text { Keith } & 3 & 2 & 1 \\\\\text { Sam } & 1 & 2 & 2 \\\\\text { Cody } & 2 & 1 & 2\\\\\hline\end{array}$$ The sale prices are \(\$ 14.95\) per shirt, \(\$ 18.95\) per sweater, and \(\$ 24.95\) per jacket. In their state, there is no sales tax on purchases of clothing. Use matrix multiplication to determine the total expenditure of each of the three shoppers.

An electronics firm makes a clock radio in two different models: one (model 380 ) with a battery backup feature and the other (model 360 ) without. It takes 1 hour and 15 minutes to manufacture each unit of the model 380 radio, and only 1 hour to manufacture each unit of the model \(360 .\) At least 500 units of the model 360 radio are to be produced. The manufacturer realizes a profit per radio of \(\$ 15\) for the model 380 and only \(\$ 10\) for the model \(360 .\) If at most 2000 hours are to be allocated to the manufacture of the two models combined, how many of each model should be made to maximize the total profit?

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