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Write the partial fraction decomposition of each rational expression. $$\frac{6 x^{2}-8 x+24}{x^{4}-16}$$

Short Answer

Expert verified
\(\frac{3}{x - 2} + \frac{3}{x + 2} + \frac{2}{x^{2} + 4}\)

Step by step solution

01

Factor the denominator

Start by factoring the denominator as it is a difference of two squares. We know that \(a^2 - b^2 = (a - b)(a + b)\). Thus, we can rewrite \(x^{4} - 16\) as \((x^{2} - 4)(x^{2} + 4)\). Further, since \(x^{2} - 4\) is again a difference of squares, it can be factored as \((x - 2)(x + 2)\). Hence the denominator becomes \((x - 2)(x + 2)(x^{2} + 4)\).
02

Write a general form of decomposition

The next step is to write the general form of decomposition. As the denominator has a linear factor \((x - 2), (x + 2)\) and a quadratic factor \((x^{2} + 4)\), the general form of decomposition will be given by: \(\frac{6x^{2} - 8x + 24}{(x - 2)(x + 2)(x^{2} + 4)} = \frac{A}{x - 2} + \frac{B}{x + 2} + \frac{Cx + D}{x^{2} + 4}\), where A, B, C and D are constants to be determined.
03

Find constants using the equation

Multiply both sides by the denominator \((x - 2)(x + 2)(x^{2} + 4)\) to clear it out. This gives us: \(6x^{2} - 8x + 24 = A(x + 2)(x^{2} + 4) + B(x - 2)(x^{2} + 4) + (Cx + D)(x - 2)(x + 2)\). Equating the constants and coefficients of both sides, we get a system of four linear equations with four variables A, B, C and D. Solve this system to find the values of A, B, C and D. In this case, A = 3, B = 3, C = 0 and D = 2.
04

Write out the partial fraction decomposition

Substitute the values of A, B, C and D back into the general form of decomposition to obtain the final decomposition. So, \(\frac{6x^{2} - 8x + 24}{(x - 2)(x + 2)(x^{2} + 4)} = \frac{3}{x - 2} + \frac{3}{x + 2} + \frac{2}{x^{2} + 4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Expressions
Rational expressions are fractions where both the numerator and the denominator are polynomials.
These often appear in math problems related to algebra and calculus.

When dealing with rational expressions, it's essential to understand how to manipulate them to solve various math problems, such as simplifying expressions, finding common denominators, or performing partial fraction decomposition.
Partial fraction decomposition involves breaking down a complex rational expression into simpler fractions that are easier to work with.

This technique is beneficial when you're integrating rational functions or solving specific differential equations. The original exercise is a perfect example of using partial fraction decomposition to simplify rational expressions into parts, each with an easily recognizable denominator.
Factorization
Factorization is a key step in handling rational expressions and understanding partial fraction decomposition.
It involves breaking down a polynomial into simpler polynomials that multiply together to give the original polynomial.

**Difference of Squares**
A common factorization pattern is the difference of squares, expressed as \(a^2 - b^2 = (a-b)(a+b)\). Recognizing and applying this pattern allows you to simplify the original polynomial expression.

For example, in the exercise, the original expression \(x^4 - 16\) is factored as \((x^2 - 4)(x^2 + 4)\), which further factors to \((x-2)(x+2)(x^2+4)\). Each factor is inspected for further factoring possibilities.
Understanding factorization makes it significantly easier to handle complex polynomial expressions and set up the groundwork for decomposition.
Linear Equations
Linear equations play a crucial role when breaking down rational expressions into partial fractions.
While factoring, you arrive at expressions with unknown constants such as \(A\), \(B\), \(C\), and \(D\).

**Creating Equations**
The next step involves setting up equations that help find these constants by equating the original numerator to the expression obtained from multiplying each part of the decomposition by the common denominator.
This results in a system where each coefficient of powers of \(x\) in the resulting expressions aligns.

**Example**
In our case, you equate \(6x^2 - 8x + 24\) with \(A(x + 2)(x^2 + 4) + B(x - 2)(x^2 + 4) + (Cx + D)(x - 2)(x + 2)\).
This approach simplifies the process of determining each unknown constant in the decomposition.
Systems of Equations
Once you set up linear equations for each unknown constant during decomposition, solving them typically involves dealing with systems of equations.
In partial fraction decomposition, especially with multiple unknowns, you encounter a system of linear equations.

**Solving the System**
Solving this system requires aligning coefficients of like terms from both sides of the equation. Each equation corresponds to a specific coefficient's value or a sum of coefficients that equals a particular term in the original polynomial.
This is done to maintain balance and consistency between both sides of the equation.

In the example exercise, solving for \(A\), \(B\), \(C\), and \(D\) yields values by matching coefficients of each term.
Applying methods such as substitution or elimination can help resolve these systems effectively.
Here, using simple algebraic manipulations helps find that \(A=3\), \(B=3\), \(C=0\), and \(D=2\). Recognizing how to efficiently solve these systems can greatly enhance your algebraic problem-solving skills.

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Most popular questions from this chapter

A financial advisor offers three specific investment instruments: a stock- based mutual fund, a high-yield bond, and a certificate of deposit (CD). Risk factors for individual instruments can be quantified on a scale of 1 to \(5,\) with 1 being the most risky. The risk factors associated with these particular instruments are summarized in the following table.$$\begin{array}{lc} \text { Type of Investment } & \text { Risk Factor } \\ \text { Stock-based mutual fund } & 3 \\\\\text { High-yield bond } & 1 \\\\\text { CD } & 5\end{array}$$.One of the advisor's clients can tolerate an overall risk level of \(3.5 .\) In addition, the client stipulates that the amount of money invested in the mutual fund must equal the sum of the amounts invested in the high-yield bond and the CD. To satisfy the client's requirements, what percentage of the total investment should be allocated to each instrument?

You wish to make a 1 -pound blend of two types of coffee, Kona and Java. The Kona costs \(\$ 8\) per pound and the Java costs \(\$ 5\) per pound. The blend will sell for \(\$ 7\) per pound. (a) Let \(k\) and \(j\) denote the amounts (in pounds) of Kona and Java, respectively, that go into making a 1 -pound blend. One equation that must be satisfied by \(k\) and \(j\) is $$k+j=1$$ Both \(k\) and \(j\) must be between 0 and \(1 .\) Why? (b) Using the variables \(k\) and \(j\), write an equation that expresses the fact that the total cost of 1 pound of the blend will be \(\$ 7\) (c) Solve the system of equations from parts (a) and (b), and interpret your solution. (d) To make a 1 -pound blend of Kona and Java that costs \(\$ 7.50\) per pound, which type of coffee would you use more of? Explain without solving any equations.

Apply elementary row operations to a matrix to solve the system of equations. If there is no solution, state that the system is inconsistent. $$\left\\{\begin{array}{c}x+2 y+z=-3 \\ 3 x+y-2 z=2 \\ 4 x+3 y-z=0\end{array}\right.$$

Find \(\left(A^{2}\right)^{-1}\) and \(\left(A^{-1}\right)^{2},\) where \(A=\left[\begin{array}{rr}1 & -2 \\ -1 & 3\end{array}\right] .\) What do you observe? Use the definition of the inverse of a matrix, together with the fact that \((A B)^{-1}=A^{-1} B^{-1},\) to show that \(\left(A^{2}\right)^{-1}=\left(A^{-1}\right)^{2}\) for every square matrix \(A\)

The sum of money invested in two savings accounts is \(\$ 1000 .\) If both accounts pay \(4 \%\) interest compounded annually, is it possible to earn a total of \(\$ 50\) in interest in the first year? (a) Explain your answer in words. (b) Explain your answer using a system of equations.

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