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Use elimination to solve each system of equations. Check your solution. $$\left\\{\begin{array}{r} 3 x-y=9 \\ x+y=-1 \end{array}\right.$$

Short Answer

Expert verified
The solution to the system of equations is \(x = 2\) and \(y = -3\). The check at the end proves that the solution is correct.

Step by step solution

01

Preparing the Equations

Write out the two equations from the system: \[3x - y = 9\] and \[x + y = -1\]
02

Applying the Elimination

Sum up the two equations: \[(3x - y) + (x + y) = 9 + (-1)\]. This simplifies to \[4x = 8\]
03

Solve for x

Isolate x by dividing by 4 on both sides: \[x = 8 / 4\]. We find that \[x = 2\]
04

Solve for y

Substitute x into one of the original equations, for instance the second one, to find the value of y: \[2 + y = -1\]. Therefore, \[y = -1 - 2\] we find that \[y = -3\]
05

Check Solution

Substitute the obtained values for x and y into both original equations to check the solution. First for \[3x - y = 9\], the equation becomes \[3*2 - (-3) = 9\], which simplifies to 9 = 9. Then for \[x + y = -1\], it becomes \[2 - 3 = -1\], which also simplifies to -1 = -1

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elimination Method
The elimination method is a popular technique to solve systems of linear equations. The goal is to eliminate one of the variables, making it easier to solve for the other. Here's how it works:

To use elimination, we think about combining the equations in such a way that one of the variables cancels out.
This often involves adding or subtracting the equations from each other. For example, in the given system
  • 3x - y = 9
  • x + y = -1
we can add the two equations. Notice how the "+y" and "-y" terms will cancel each other. The result is a new equation with only one variable: 4x = 8.

With one variable gone, finding the value of x or y becomes straightforward. This method is efficient and reduces the complexity of the system. Once we find one variable, we plug it back into one of the original equations to solve for the other variable. This makes the elimination method very powerful for solving linear equations quickly.
Solving Linear Equations
Solving linear equations is all about finding values for variables that make the equation true.
Linear equations typically take the form of ax + by = c. Each letter represents a constant or coefficient that helps define the relationship between x and y.

In the elimination method example, once we isolated the equation 4x = 8, we solved for x by dividing both sides by 4, which gives us x = 2.
  • Begin by isolating one of the variables on one side of the equation, if needed.
  • In this case, we already have 4x on one side, so dividing by 4 simplifies it further.
Once x is determined, solving for y involves substituting x back into one of the original equations. In this example, substituting x = 2 into x + y = -1 helps us find y = -3. Solving linear equations involves manipulating the equations carefully to find accurate values for all variables involved.
Checking Solutions
Once we have proposed solutions for x and y, the next step is to verify these values to ensure they satisfy the original equations. This step, known as checking solutions, is crucial to confirm our solutions are correct.

We substitute the values of x and y back into both original equations:
  • For 3x - y = 9, substituting x = 2 and y = -3 gives us 3(2) - (-3) = 9, which simplifies to 6 + 3 = 9. Hence, the equation holds true.
  • For x + y = -1, substituting x = 2 and y = -3 gives 2 - 3 = -1, confirming this equation is also correct.
Checking solutions ensures that our arithmetic is correct and the solutions make sense in the context of the problem. It validates that both equations in the system are satisfied with the obtained values of x and y. This final step gives confidence in the accuracy of our solutions and reinforces understanding of the solving process.

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Most popular questions from this chapter

Apply elementary row operations to a matrix to solve the system of equations. If there is no solution, state that the system is inconsistent. $$\left\\{\begin{array}{l}-x+2 y-3 z=2 \\ 2 x+3 y+2 z=1 \\ 3 x+y+5 z=1\end{array}\right.$$

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Find \(A^{2}\) (the product \(A A\) ) and \(A^{3}\) (the prod\(\left.u c t\left(A^{2}\right) A\right)\). $$A=\left[\begin{array}{rr}-4 & 0 \\\0 & 3\end{array}\right]$$

The following table lists the caloric content of a typical fast-food meal. Food (single serving) Calories Cheeseburger Medium order of fries Medium cola (21 oz) \(\begin{array}{lc}\text { Food (single serving) } & \text { Calories } \\\ \text { Cheeseburger } & 330 \\ \text { Medium order of fries } & 450 \\\ \text { Medium cola }(210 z) & 220\end{array}\) (a) After a lunch that consists of a cheeseburger, a medium order of fries, and a medium cola, you decide to burn off a quarter of the total calories in the meal by some combination of running and walking. You know that running burns 8 calories per minute and walking burns 3 calories per minute. If you exercise for a total of 40 minutes, how many minutes should you spend on each activity? (b) Rework part (a) for the case in which you exercise for a total of only 20 minutes. Do you get a realistic solution? Explain your answer.

In this set of exercises, you will use the method of solving linear systems using matrices to study real-world problems. An electronics store carries two brands of video cameras. For a certain week, the number of Brand A video cameras sold was 10 less than twice the number of Brand B cameras sold. Brand A cameras cost \(\$ 200\) and Brand \(B\) cameras cost \(\$ 350 .\) If the total revenue generated that week from the sale of both types of cameras was \(\$ 16,750,\) how many of each type were sold?

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