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Perform each operation, given \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) $$\mathbf{u}=\langle 3,2\rangle, \mathbf{v}=\langle-1,4\rangle, \mathbf{w}=\langle-2,-1\rangle$$ $$-\mathbf{u} \cdot(\mathbf{v}+\mathbf{w})$$

Short Answer

Expert verified
The result of the operation \(-\mathbf{u} \cdot(\mathbf{v}+\mathbf{w})\) is 3.

Step by step solution

01

Perform Vector Addition

Add the vectors \( \mathbf{v} \) and \( \mathbf{w} \) together. Applying vector addition to \(\mathbf{v}\) and \(\mathbf{w}\), we add their corresponding components. Therefore, \( \mathbf{v} + \mathbf{w} = \langle -1, 4\rangle + \langle -2, -1\rangle = \langle -1-2, 4-1\rangle = \langle -3, 3 \rangle \).
02

Perform Scalar Multiplication

Multiply the vector \( -\mathbf{u} \) with the resulting vector from step 1. In order to do so, we get \( -\mathbf{u} = -1 \cdot \langle 3,2\rangle = \langle -3,-2 \rangle \).
03

Apply the Dot Product

Finally, calculate the dot product of vector -u and the result obtained in the first step by multiplying their corresponding components and adding them. That is, \( -\mathbf{u} \cdot (\mathbf{v}+\mathbf{w}) = \langle -3,-2 \rangle \cdot \langle -3, 3 \rangle = (-3*-3) + (-2*3) = 9 - 6 = 3. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
Vector addition is a fundamental operation in mathematics, particularly in precalculus, where vectors are often used to represent quantities that have both magnitude and direction. This operation can be visualized by placing the tail of one vector at the head of another and drawing the resultant vector from the tail of the first to the head of the second vector.

To perform vector addition algebraically, simply add the corresponding components of each vector. For example, suppose we have two vectors in a 2-dimensional space, \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \). The sum of these vectors is given by \( \mathbf{a} + \mathbf{b} = \langle a_1+b_1, a_2+b_2 \rangle \).

In the context of the given exercise, vector addition is used when combining vectors \( \mathbf{v} \) and \( \mathbf{w} \). This is done by adding their respective components, resulting in the new vector \( \langle -3, 3 \rangle \) which represents the combined effect of \( \mathbf{v} \) and \( \mathbf{w} \).

Remember

While adding vectors, keep in mind that the addition is commutative, meaning that \( \mathbf{a} + \mathbf{b} = \mathbf{b} + \mathbf{a} \), as it does not matter in which order the vectors are added.
Scalar Multiplication
Scalar multiplication is the process of multiplying a vector by a scalar (a real number), which changes the magnitude of the vector but not its direction, unless the scalar is negative, in which case the direction is reversed.

To multiply a vector by a scalar, you simply multiply each component of the vector by the scalar. For instance, if we have a scalar \( c \) and a vector \( \mathbf{x} = \langle x_1, x_2 \rangle \), then the scalar multiplication is \( c\mathbf{x} = \langle cx_1, cx_2 \rangle \).

In our given exercise, scalar multiplication comes into play when we multiply the vector \( \mathbf{-u} \) by -1. This operation flips the vector in the opposite direction due to the negative scalar, producing a new vector, \( \langle -3, -2 \rangle \) from \( \mathbf{u} \) which initially was \( \langle 3, 2 \rangle \).

Key Point

It is crucial to understand that scalar multiplication affects both the magnitude and the direction (in case of a negative scalar), and the result is still a vector in the same or opposite direction.
Dot Product
The dot product, also called the scalar product, is a way of multiplying two vectors that results in a scalar. This operation measures the magnitude of one vector in the direction of another and is used extensively in physics, engineering, and computer graphics, among other fields.

To calculate the dot product of two vectors, you multiply the corresponding components of the vectors and then sum up these products. Given two 2-dimensional vectors \( \mathbf{p} = \langle p_1, p_2 \rangle \) and \( \mathbf{q} = \langle q_1, q_2 \rangle \), their dot product is \( \mathbf{p} \cdot \mathbf{q} = p_1q_1 + p_2q_2 \).

In our exercise, we are calculating the dot product of vectors \( \mathbf{-u} \) and \( \mathbf{v}+\mathbf{w} \), which requires taking the sum of the products of their respective components, resulting in the scalar value 3. The dot product tells us about the alignment of the two vectors: if the dot product is positive, the vectors are pointing in more or less the same direction; if negative, they point in opposite directions; and if zero, they are orthogonal (at a right angle to each other).

Practical Usage

The dot product can be particularly useful for determining the angle between two vectors, as it is related to the cosine of the angle between them. When the dot product is zero, the vectors are perpendicular, a valuable piece of information in many geometric scenarios.

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Most popular questions from this chapter

Round your answers to two decimal places. Wanda goes for a hike. She first walks 2.4 miles in the direction \(S 17^{\circ} \mathrm{E}\) and then goes another 1.8 miles in the direction \(\mathrm{S} 38^{\circ} \mathrm{E}\). (a) By what east-west distance did Wanda's position change between the time she began the hike and the time she completed it? (b) By what north-south distance did Wanda's position change? (c) At the end of the hike, how far is Wanda from her starting point? (d) Suppose that Wanda traverses a single straight-line path and that her starting point and ending point are the same as before. In what direction does she walk?

Find the magnitude and direction of each of the given vectors. Express the direction as an angle \(\theta\) in standard position, where \(0^{\circ} \leq \theta<360^{\circ},\) to tuo decimal places. $$\mathbf{v}=-3.2 \mathbf{i}+2 \mathbf{j}$$

Use De Moivre's Theorem to find each expression. $$(1+i)^{4}$$

Round your answers to two decimal places. A glider traveling at 90 miles per hour in the direction \(\mathrm{N} 20^{\circ} \mathrm{W}\) encounters a mild wind with speed 15 miles per hour. If the wind is traveling from east to west, find the resulting speed of the glider and its direction.

This set of exercises will draw on the ideas presented in this section and your general math background. Explain why you cannot use the Law of Sines to solve an oblique triangle if you are given only the three sides of the triangle (SSS) and no two of them are of equal length.

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