Chapter 7: Problem 29
Use De Moivre's Theorem to find each expression. $$(1+i)^{4}$$
Short Answer
Expert verified
The result of \((1 + i)^4\) is -4.
Step by step solution
01
Convert Complex Number to Polar Form
The complex number is given as \(1 + i\). First, calculate the modulus \(r\), \(r = \sqrt{a^2 + b^2} = \sqrt{1^2 + 1^2} = \sqrt{2}\). Now calculate the argument \(\theta\), using the formula \(\tan^{-1}(b/a)\), which gives \(\tan^{-1}(1/1) = \pi/4\). Therefore, the complex number can be expressed in polar form as \(\sqrt{2}(\cos(\pi/4) + i \sin(\pi/4))\)
02
Apply De Moivre's Theorem
According to De Moivre's theorem, raising a complex number to a power is the same as raising its modulus to the power and multiplying its argument by the power. Therefore, \((1 + i)^4 = \sqrt{2}^4(\cos(4 \cdot \pi/4) + i \sin(4· \pi/4)) = 4(\cos(\pi) + i \sin(\pi))\)
03
Convert back to Rectangular Form
Now this must be converted back to rectangular form x + yi. Use the definitions \(\cos(\pi) = -1\) and \(\sin(\pi) = 0\) to get \(4(\cos(\pi) + i \sin(\pi)) = 4(-1 + 0i) = -4\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers may sound complicated, but they're simply a combination of a real number and an imaginary number. They're usually written in the form \(a + bi\), where:
When working with problems involving exponential powers of complex numbers, it's often advantageous to express these numbers in a different form known as polar form.
- \(a\) is the real part.
- \(b\) is the imaginary part.
- \(i\) is the imaginary unit, with the property \(i^2 = -1\).
When working with problems involving exponential powers of complex numbers, it's often advantageous to express these numbers in a different form known as polar form.
Polar Coordinates
Polar coordinates offer a unique way to think about complex numbers. Instead of expressing a complex number as \(a + bi\), a polar representation uses a radius (or modulus) and an angle (or argument). Here's how it works:
- The modulus \(r\) of the complex number \(a + bi\) is calculated as \(\sqrt{a^2 + b^2}\). This represents the distance from the origin to the point in the complex plane.
- The argument \(\theta\) is the angle formed with the positive real axis, and it can be calculated using \(\tan^{-1}(\frac{b}{a})\).
Modulus and Argument
The terms 'modulus' and 'argument' are crucial for understanding the polar form of a complex number.
- The modulus \(r\) measures the magnitude or length of the vector in the complex plane. For \(1 + i\), the modulus is computed as \(\sqrt{1^2 + 1^2} = \sqrt{2}\).
- The argument \(\theta\) indicates the direction of the vector, given by the angle it forms with the positive real axis. For \(1 + i\), this is \(\pi/4\).