/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Solve the quadratic equation by ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the quadratic equation by using the quadratic formula. Find only real solutions. $$-2+t^{2}+t=0$$

Short Answer

Expert verified
The real solutions to the equation are \(t = -2\) and \(t = 1/2\).

Step by step solution

01

Identify the coefficients

In the given quadratic equation, \(-2 + t^{2} + t = 0\), we can rewrite it in the standard form as \(t^{2}+t-2 = 0\). So we can identify the coefficients as \(a = 1\), \(b = 1\) and \(c = -2\).
02

Determine the determinant

Calculate the discriminant, which is \(b^{2}-4ac\). Thus, discriminant equals to \(1^{2}-4(1)(-2)= 1+8=9\).
03

Apply the Quadratic Formula

Plugging the coefficients \(a\), \(b\) and \(c\) into the quadratic formula, solving it would give the solutions to the equation. This gives us \(t = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} = \frac{-1 \pm \sqrt{9}}{2} = -1 \pm \frac{3}{2}\). This simplifies to \(t = -2\) or \(t = 1/2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Quadratic equations are often presented in the standard form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \), represent known values and \( a \) is not equal to zero. The solutions to these equations, also known as 'roots', are the values of \( x \) that make the equation true. The widely recognized method for solving these equations is the quadratic formula: \[ x = \frac{{-b \pm \sqrt{{b^2-4ac}}}}{{2a}} \]

To solve these equations, three main steps are commonly followed: identifying coefficients, calculating the discriminant, and then applying the Quadratic Formula. By following these steps, we can ensure that we find the most accurate solutions possible, whether they are real numbers or complex numbers. It's essential to perform each step carefully to avoid errors that might lead to incorrect solutions.
Discriminant in Quadratics
The discriminant of a quadratic equation, symbolized by \( D \), is a part of the quadratic formula and is given by the expression \( b^2 - 4ac \). It holds a crucial role in determining the nature and number of the solutions of the equation.

  • If \( D > 0 \), the quadratic equation has two distinct real solutions.
  • If \( D = 0 \), the equation has exactly one real solution.
  • If \( D < 0 \), the equation has two complex solutions and no real solutions.
In our example, the discriminant is \( 9 \), which is positive, hence the equation \( t^2 + t - 2 = 0 \) has two distinct real solutions. Understanding the discriminant is key to predicting the number and type of solutions without actually solving the equation.
Real Solutions of Quadratics
Real solutions of a quadratic equation are the \( x \) values that satisfy the equation when plotted on a real number line. It's possible when the discriminant \( D \), \( b^2 - 4ac \), is greater than or equal to zero, as nonnegative discriminants indicate real number solutions.

Following the quadratic formula and the discriminant, we determine the real solutions by performing operations included in the formula. In our exercise, we found two real solutions \( t = -2 \) and \( t = 1/2 \). These solutions are the points where the graph of the quadratic equation \( t^2 + t - 2 = 0 \) intersects with the \( t \) axis. This concept is essential as understanding real solutions helps us analyze and interpret the behavior of quadratic functions in practical scenarios.

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Most popular questions from this chapter

Graph each quadratic function by finding a suitable viewing window with the help of the TABLE feature of a graphing utility. Also find the vertex of the associated parabola using the graphing utility. $$y_{1}(x)=0.4 x^{2}+20$$

Examine the following table of values for a quadratic function \(f\) $$\begin{array}{rr} x & f(x) \\ -2 & 3 \\ -1 & 0 \\ 0 & -1 \\ 1 & 0 \\ 2 & 3 \end{array}$$ (a) What is the equation of the axis of symmetry of the associated parabola? Justify your answer. (b) Find the minimum or maximum value of the function and the value of \(x\) at which it occurs. (c) Sketch a graph of the function from the values given in the table, and find an expression for the function.

This set of exercises will draw on the ideas presented in this section and your general math background. Without doing any calculations, explain why $$\sqrt{x+1}=-2$$ does not have a solution.

The shape of the Gateway Arch in St. Louis, Missouri, can be approximated by a parabola. (The actual shape will be discussed in an exercise in the chapter on exponential functions.) The highest point of the arch is approximately 625 feet above the ground, and the arch has a (horizontal) span of approximately 600 feet. (Check your book to see image) (a) Set up a coordinate system with the origin at the midpoint of the base of the arch. What are the \(x\) -intercepts of the parabola, and what do they represent? (b) What do the \(x\)- and \(y\)-coordinates of the vertex of the parabola represent? (c) Write an expression for the quadratic function associated with the parabola. (Hint: Use the vertex form of a quadratic function and find the coefficient \(a .)\) (d) What is the \(y\)-coordinate of a point on the arch whose (horizontal) distance from the axis of symmetry of the parabola is 100 feet?

A rectangular garden plot is to be enclosed with a fence on three of its sides and an existing wall on the fourth side. There is 45 feet of fencing material available. (a) Write an equation relating the amount of available fencing material to the lengths of the three sides that are to be fenced. (b) Use the equation in part (a) to write an expression for the width of the enclosed region in terms of its length. (c) For each value of the length given in the following table of possible dimensions for the garden plot, fill in the value of the corresponding width. Use your expression from part (b) and compute the resulting area. What do you observe about the area of the enclosed region as the dimensions of the garden plot are varied? $$\begin{array}{ccc}\hline \begin{array}{c}\text { Length } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Width } \\\\\text { (feet) }\end{array} & \begin{array}{c}\text { Total Amount of } \\\\\text { Fencing Material (feet) }\end{array} & \begin{array}{c}\text { Area } \\\\\text { (square feet) }\end{array} \\\\\hline 5 & & 45 \\\10 & & 45 \\\15 & & 45 \\\20 & & 45 \\\30 & & 45 \\\k & & 45 \\\& &\end{array}$$ (d) Write an expression for the area of the garden plot in terms of its length. (e) Find the dimensions that will yield a garden plot with an area of 145 square feet.

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