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In Exercises \(5-25,\) prove the statement by induction. \(n^{2}+n\) is even

Short Answer

Expert verified
Proof by mathematical induction is a common method which is used to prove statements about all positive integers. By showing the base case \(n=1\) is true, assuming the statement is true for \(n=k\), and proving it for \(n=k+1\), we can conclude that the statement \(n^{2}+n\) is even for all positive integers \(n\).

Step by step solution

01

Proving the Base Case

Start by proving the base case. The base case here will be \(n=1\). Apply \(n=1\) to the given expression \(n^{2}+n\), which yields \(1^2 + 1 = 2\). The number 2 is even, therefore the base case is proven.
02

Making an Assumption for Inductive Hypothesis

Assume that the statement is true for some positive integer \(k\), i.e., \(k^{2}+k\) is an even number. This assumption is known as the Inductive Hypothesis.
03

Proof by Induction

Now, try to prove it for the next integer \(k+1\). To do that, substitute \(n=k+1\) into the expression, it becomes \((k+1)^{2}+(k+1)=k^{2}+2k+1+k+1 = (k^{2}+k)+(2k+2)\). Since both \(k^{2}+k\) (from inductive hypothesis) and \(2k+2\) are even, therefore, the sum is even, and the inductive step is proved.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proof by Induction
Understanding the concept of mathematical induction is key to many areas of mathematics, especially when proving statements for whole numbers. It has two essential steps: the base case and the inductive step.

For the base case, one verifies that the statement holds true for an initial value, often at the smallest value, such as 1. In our exercise, we saw that by plugging in 1 for n, the statement held true. Next comes the assumption step, where we presume the statement is true for some integer k, which paves the way for the inductive step. In this phase, we aim to prove the statement for k+1, thereby showing a sort of 'domino effect' – if the statement is true for one number, it's true for the next, and so on, indefinitely. This principle fundamentally relies on the well-ordering principle of the natural numbers, which states that every non-empty set of natural numbers has a least element.

While simple in concept, careful attention must be paid to forming a correct hypothesis and carrying through the inductive step. Sometimes, additional assumptions or algebraic manipulations may be necessary to facilitate the proof. It's imperative that at each stage, clarity of logical steps is maintained to ensure a solid understanding and a correct conclusion.
Basic Algebra
Basic algebra is the backbone of solving mathematical problems involving equations and expressions. In our example, understanding how to expand and simplify an expression was vital. Starting with \(n=k+1\), the expression expands using the distributive property of multiplication over addition, resulting in \(k+1)^{2}+(k+1)=k^{2}+2k+1+k+1\). From there, combining like terms—which are terms that share the same variables and exponents—is crucial.

To prove our argument, we recognized that the expression could be split into two parts: \(k^{2}+k\), our inductive hypothesis, and \(2k+2\), a clear even number since it is 2 multiplied by another whole number. Recognizing that the sum of two even numbers is always even ties in fundamental concepts from arithmetic and number properties.

The ability to manipulate equations and expressions with algebraic operations is a foundational skill that makes higher mathematics accessible, emphasizing the importance of mastering these basics for more complex problem-solving.
Number Theory
Number theory delves into the properties and patterns of integers. Evenness and oddness are precursory ideas in this field, where an even number is defined as any integer that is divisible by 2 without leaving a remainder. In this light, proving that \(n^{2}+n\) is even for any positive integer n directly applies a principle of number theory.

By splitting the expression into two parts: \(n^{2}\) and n, where n stands for any positive integer, we can reason about the nature of these parts. If n is even, then both \(n^{2}\) and n are even, and their sum is even. If n is odd, then \(n^{2}\) is also odd, but adding n, another odd number, results in an even sum. This type of reasoning showcases how we can use established properties of numbers to make broader conclusions.

The beauty of number theory lies in its simplicity and depth simultaneously. Its fundamental concepts serve as building blocks that, when combined with other areas of mathematics like algebra, can lead to profound and often surprisingly elegant solutions to complex problems.

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