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The 2005 Mitsubishi Eclipse has a combined city and highway mileage rating of 26 miles per gallon. Write a formula for the distance an Eclipse can travel (in miles) as a function of the amount of gasoline used (in gallons). (Source: www.fueleconomy.gov)

Short Answer

Expert verified
The formula for the distance an Eclipse can travel (in miles) as a function of the amount of gasoline used (in gallons) is D = 26 * G.

Step by step solution

01

Identify the known variables

In this case, the known variable is the fuel economy of the Mitsubishi Eclipse, which is 26 miles per gallon.
02

Establish the relationship

The distance covered (D) is directly proportionate to the amount of gas used (G). This relationship can be written as D = m * G, where m is the constant of proportionality.
03

Determine the constant of proportionality

In this case, m equals the fuel efficiency of the car, which is 26 miles per gallon. Therefore, m = 26.
04

Write the function

Substituting the value of m into the equation gives the formula D = 26 * G, where G is the amount of gas used.
05

Interpret the function

The function D = 26 * G means that for each gallon of gas, the car can travel 26 miles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fuel Economy
Fuel economy is a crucial concept when discussing vehicles and their efficiency. It refers to how far a car can travel per unit of fuel. It is most commonly expressed in miles per gallon (mpg). This measurement gives us an idea of the car's efficiency—how well it uses fuel compared to other vehicles. A higher mpg value means that the car can travel a longer distance on less fuel, which is great for saving on fuel costs and minimizing environmental impact.

In our example, the 2005 Mitsubishi Eclipse has a fuel economy of 26 mpg. This implies that on average, the car uses one gallon of gasoline to travel 26 miles. Understanding fuel economy is important for making informed decisions when purchasing a car, as well as planning trips to maximize fuel usage.
Proportionality
Proportionality is a mathematical concept that helps us understand relationships between different quantities. When we say two variables are proportionate, it means that as one variable changes, the other changes in a consistent way. In simpler terms, if you double one variable, the other also doubles, and so on.

In the case of fuel economy, we describe the relationship between distance traveled (D) and gasoline used (G) as directly proportional. The equation \( D = m \times G \) captures this relationship, where \( m \) is the constant of proportionality. Here, \( m \) is 26 miles per gallon, indicating that for each gallon of fuel, the car travels 26 miles. Understanding proportionality helps in predicting outcomes accurately based on variable changes.
Mileage Calculation
Mileage calculation involves figuring out the total distance a vehicle can travel based on the amount of fuel consumed. Using the fuel economy as a constant of proportionality, we can determine how much distance can be covered with a specified amount of fuel.

For the Mitsubishi Eclipse, we use the formula \( D = 26 \times G \), where \( D \) is the distance traveled, and \( G \) is the gallons of gasoline used. If you know the gallons of gasoline available, simply multiply by 26 to find out how many miles you can drive. For example, with 2 gallons, the Eclipse can travel \( 26 \times 2 = 52 \) miles.
Variables Identification
Identifying variables correctly is a fundamental step in solving mathematical problems involving functions. In our fuel economy exercise, the variables are clear: the amount of fuel used, denoted as \( G \), and the distance traveled, denoted as \( D \).

Recognizing that \( G \) represents gallons and \( D \) stands for distance allows us to apply the formula correctly. The constant \( m \), which is the fuel efficiency of the Eclipse at 26 miles per gallon, connects these variables within the function. Accurately identifying and understanding these variables is essential in creating and using mathematical models effectively in real-life applications.

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Most popular questions from this chapter

Car Ownership Costs In this problem, you will investigate whether it is cost effective to purchase a car that gets better gasoline mileage, even though its purchase price may be higher. A 2003 Subaru Outback wagon costs \(\$ 23,500\) and gets 22 miles per gallon. A 2003 Volkswagen Passat wagon costs \(\$ 24,110\) and gets 25 miles per gallon. Assume that gasoline costs \(\$ 4\) per gallon. (Sources: Edmunds.com and U.S. Environmental Protection Agency) (a) What is the cost of gasoline per mile for the Outback wagon? the Passat wagon? (b) Assume that the total cost of owning a car consists of the price of the car and the cost of gasoline. For each car, find a linear function describing the total cost, with the input variable being the number of miles driven. (c) What is the slope of the graph of each function in part (b), and what do the slopes signify? (d) How many miles would you have to drive for the total cost of the Passat to be the same as that of the Outback?

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This set of exercises will draw on the ideas presented in this section and your general math background. Show that \(|x-k|=|k-x|\), where \(k\) is any real number.

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