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Convert the equation into continuous growth form, \(f(t)=a e^{k t}\). $$ f(t)=1400(1.12)^{t} $$

Short Answer

Expert verified
The continuous growth form is \(f(t) = 1400 e^{0.1133 t}\).

Step by step solution

01

Identify the Initial Value

Start by identifying the initial value, \(a\), from the given equation. In the equation \(f(t) = 1400(1.12)^t\), the initial value \(a\) is 1400.
02

Recognize the Rate Component

Recognize that \(1.12\) is the growth factor per time period in the equation \(f(t) = 1400(1.12)^t\). Our goal is to express this in terms of \(e^{kt}\).
03

Relate Growth Factor to Exponential Form

Understand that the term \((1.12)^t\) needs to be rewritten in the exponential \(e^{kt}\) form. We need to find \(k\) such that \((1.12)^t = (e^k)^t\). This equates to \(1.12 = e^k\).
04

Solve for k

To solve for \(k\), take the natural logarithm of both sides: \(\ln(1.12) = \ln(e^k)\). This simplifies to \(k = \ln(1.12)\). Calculate \(k\) using a calculator: \(k \approx 0.1133\).
05

Reconstruct the Continuous Growth Equation

Now, write the continuous growth form using the values obtained: \(f(t) = 1400 e^{0.1133 t}\). This equation represents the same growth process as the original one in continuous form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
Exponential growth is a process that increases quantity over time; it is often described by mathematical equations. In the context of functions, exponential growth occurs when the rate of increase is proportional to the current quantity. This means that as the quantity grows, the rate at which it grows also increases.

The equation that represents exponential growth is of the form: \[ f(t) = a imes b^t \] where:
  • \( f(t) \) is the value at time \( t \)
  • \( a \) is the initial value or starting amount
  • \( b \) is the growth factor
  • \( t \) is the time variable
The equation can also be expressed in continuous form, like \( f(t) = a \, e^{k t} \), using the natural base \( e \). This representation is particularly useful for continuous growth processes.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is the logarithm to the base \( e \), where \( e \) is Euler's number, approximately 2.71828. In mathematical terms, \( \ln(x) \) means 'the power to which \( e \) must be raised to equal \( x \)'.

Natural logarithms are commonly used in exponential growth calculations, especially when converting growth rates to continuous growth forms. For example, to find the continuous growth rate \( k \) from a growth factor \( b \), you would solve \( b = e^k \).

Taking the natural logarithm of both sides gives: \[ \ln(b) = k \] Natural logarithms simplify complex growth calculations and offer a practical way to express compounding effects. They are a critical tool in both mathematical and real-world applications, such as finance and population studies.
Growth Factor
The growth factor is a significant component in identifying how much a quantity increases over each time period. In the exponential growth equation \( f(t) = a \, b^t \), the growth factor is represented by \( b \). A growth factor greater than 1 indicates growth, while a number between 0 and 1 suggests decay. If \( b = 1.12 \), this implies a 12% increase per period.

Converting this to continuous form involves expressing it as an exponential function with base \( e \). Setting the relationships gives us \( b = e^k \), where \( k \) is the continuous growth rate. Solving for \( k \) requires taking the natural logarithm: \[ k = \ln(b) \] Understanding the growth factor helps us translate discrete growth models to a continuous scale, which is vital in many scientific and economic models.
Initial Value
The initial value in an exponential growth equation is the starting point or the initial quantity from which growth begins. It is represented by \( a \) in the equations \( f(t) = a \, b^t \) or \( f(t) = a \, e^{k t} \). In many physical and growth processes, determining the initial value is crucial because it serves as the baseline for all calculations.

For instance, in the function \( f(t) = 1400(1.12)^t \), the initial value is 1400. This number represents the quantity at time zero before any growth has occurred. It tells us what the starting amount was before it underwent exponential growth.

The initial value is essential in understanding and predicting future outcomes as it forms the foundation upon which the growth model is built. Having an accurate initial value ensures the reliability of any forecasts or projections derived from the growth equation.

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