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Graph each function on a semi-log scale, then find a formula for the linearized function in the form \(\log (f(x))=m x+b\). $$ f(x)=30(0.7)^{x} $$

Short Answer

Expert verified
\( \log(f(x)) = x \log(0.7) + \log(30) \) is the linearized form.

Step by step solution

01

Understand the Function

The given function is an exponential function of the form \( f(x) = a \, b^x \), where \( a = 30 \) and \( b = 0.7 \). Our task is to transform this function so that it can be graphed and analyzed on a semi-logarithmic graph.
02

Apply Logarithm to Linearize

Take the natural logarithm on both sides of the function \( f(x) = 30(0.7)^x \). This gives us: \[ \log(f(x)) = \log(30) + \log((0.7)^x) \]Using the logarithmic identity \( \log(a^b) = b\log(a) \), we get:\[ \log(f(x)) = \log(30) + x \cdot \log(0.7) \]
03

Express in Linear Form

Rewrite the expression \( \log(f(x)) = \log(30) + x \cdot \log(0.7) \) in the standard linear form, \( y = mx + b \). Here, \( y = \log(f(x)) \), \( m = \log(0.7) \), and \( b = \log(30) \). Thus, the linearized equation is:\[ \log(f(x)) = x \log(0.7) + \log(30) \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are quite distinct from regular polynomial functions. They have variables in their exponents. This allows them to grow or decay at rates that aren't constant, but rather multiplicative. An exponential function can be represented in the form \( f(x) = a \cdot b^x \).
- In this equation, \( a \) is the initial value or the y-intercept of the graph. It represents the function's value when \( x = 0 \).- The base \( b \) is the growth or decay factor. If \( b > 1 \), the function depicts growth. If \( 0 < b < 1 \), as with our original function \( f(x) = 30(0.7)^x \), it signifies decay, making the function decrease as \( x \) increases.
These functions are often used to model real-world processes like population growth, radioactive decay, or interest calculations.
Semi-Log Graphs
Semi-log graphs provide a powerful way to visualize exponential relationships. They employ a logarithmic scale on one axis, typically the y-axis, while keeping the other axis, usually the x-axis, on a regular linear scale.
- When plotting exponential functions on semi-log graphs, the graph becomes a straight line if the axes are chosen appropriately. This simplifies analysis and helps to easily interpret multiplicative relationships.- For our function \( f(x) = 30(0.7)^x \), transforming the y-values via logarithms makes identifying the rate of decrease straightforward, as the data points align linearly when plotted.
This technique is valuable in various scientific fields where exponential decay or growth needs to be analyzed accurately.
Linear Transformations
The purpose of a linear transformation within this context is to convert an exponential function into a linear equation, allowing for simpler analysis and interpretation.
- This transformation is achieved using logarithmic identities. When we apply the natural logarithm to our function \( f(x) = 30(0.7)^x \), we get \( \log(f(x)) = \log(30) + x \cdot \log(0.7) \). - In this equation, \( \log(f(x)) \) serves as our y-value, while \( x \) remains the same. This equation is now in the linear form \( y = mx + b \), with \( m = \log(0.7) \) and \( b = \log(30) \), making it straightforward to graph as a line.
This linear transformation is crucial as it simplifies finding relationships and trends within the data, making processing large sets of exponential data much more manageable.

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