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Solve for \(x\). $$ \ln (x)=-2 $$

Short Answer

Expert verified
The solution is \(x = e^{-2} \approx 0.1353\).

Step by step solution

01

Understand the Problem

The problem involves a natural logarithm equation \(\ln(x) = -2\). Our goal is to solve for \(x\) using the properties of logarithms and exponentials.
02

Exponentiate Both Sides

To eliminate the natural logarithm, exponentiate both sides using the base \(e\). This means applying the exponential function to both sides of the equation: \(e^{\ln(x)} = e^{-2}\). According to the inverse property of logarithms and exponentials, \(e^{\ln(x)} = x\).
03

Simplify

After exponentiating, the equation becomes \(x = e^{-2}\). This simplification uses the property that the exponential and the logarithmic functions are inverses.
04

Evaluate

Finally, evaluate the expression \(e^{-2}\) to get the numerical value of \(x\). Using a calculator, \(e^{-2} \approx 0.1353\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are a key part of mathematics, and they are essential when dealing with growth and decay problems. They are functions of the form \(y = a^{x}\), where \(a\) is a positive constant called the base, and \(x\) is the exponent. These functions are unique because they grow very rapidly as the value of \(x\) increases. One of the most important exponential functions is \(e^{x}\), where \(e\) is approximately equal to 2.71828. This number is known as Euler's number, and it is the base of the natural logarithm. In the context of solving equations, exponential functions often appear as part of the solution to problems involving logarithms.
Inverse Properties
Understanding inverse properties is crucial when working with logarithmic and exponential functions. An inverse property means that the operation reverses the effect of another. For instance, the natural logarithm function \(\ln(x)\) and the exponential function \(e^{x}\) are inverses of each other. This means that:
  • If you take the natural log of \(e^{x}\), you get \(x\), i.e., \(\ln(e^{x}) = x\).
  • If you exponentiate \(\ln(x)\), you return to the original number \(x\), i.e., \(e^{\ln(x)} = x\).
These inverse relationships are powerful tools for solving logarithmic equations, as demonstrated in solving \(\ln(x) = -2\) by exponentiating both sides to isolate \(x\). This simplification utilizes the property that the log and exponential cancel each other out, yielding straightforward solutions.
Solving Logarithmic Equations
Solving logarithmic equations involves using properties and manipulation to simplify and find the unknown variable. Typically, these steps include understanding the equation, such as \(\ln(x) = -2\), and then applying appropriate mathematical operations to isolate the variable. In many cases, such as this, exponentiating both sides eliminates the logarithm and reveals the variable directly.
Here’s how it works:
  • Recognize the logarithmic form and understand the need to eliminate \(\ln\) to solve for \(x\).
  • Exponentiate both sides using the base of the natural logarithm, which is \(e\). This step effectively changes \(\ln(x)\) to \(x\), because \(e^{\ln(x)} = x\).
  • Simplify the resulting expression to find \(x\).
This method is efficient and direct when dealing with natural logs and exponentials, yielding solutions that can be evaluated numerically in the final steps.
Numerical Evaluation
Numerical evaluation is the final step in solving many equations, especially when an exact symbolic solution cannot be easily expressed or when a numeric approximation is more useful. After transforming the logarithmic equation \(\ln(x) = -2\) into \(x = e^{-2}\), the next step is to find the approximate numerical value of \(x\).
Using a calculator, you can compute \(e^{-2}\), which approximates to 0.1353. This numerical result presents a tangible and practical answer to the problem. Calculators or software with scientific functions typically have the natural exponential function \(e^{x}\) built-in, allowing for quick and accurate computation. Understanding numerical evaluation helps bridge the gap between theoretical solutions and real-world applications.

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