Chapter 5: Problem 42
Explain why there does not exist a triangle with area 15 having one side of length 4 and one side of length 7 .
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Chapter 5: Problem 42
Explain why there does not exist a triangle with area 15 having one side of length 4 and one side of length 7 .
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Show that $$\cos (2 \theta) \leq \cos ^{2} \theta$$ for every angle \(\theta\).
Find an exact expression for \(\sin \frac{\pi}{24}\).
Find exact expressions for the indicated quantities. The following information will be useful: $$ \begin{array}{l} \cos 22.5^{\circ}=\frac{\sqrt{2+\sqrt{2}}}{2} \text { and } \sin 22.5^{\circ}=\frac{\sqrt{2-\sqrt{2}}}{2} \\ \cos 18^{\circ}=\sqrt{\frac{\sqrt{5}+5}{8}} \text { and } \sin 18^{\circ}=\frac{\sqrt{5}-1}{4} \end{array} $$ [The value for \(\sin 22.5^{\circ}\) used here was derived in Example 4 in Section \(5.5 ;\) the other values were derived in Exercise 64 and Problems 102 and 103 in Section \(5.5 .]\) $$\sin 82.5^{\circ}$$
Find the angle between a side of length 5 and the side with length 9 in an isosceles triangle that has one side of length 9 and two sides of length \(5 .\)
Do not make the mistake of thinking that $$\frac{\cos (2 \theta)}{2}=\cos \theta$$ is a valid identity. (a) Show that the equation above is false whenever \(0<\theta<\frac{\pi}{2}\) (b) Show that there exists an angle \(\theta\) in the interval \(\left(\frac{\pi}{2}, \pi\right)\) satisfying the equation above.
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