Chapter 4: Problem 28
What angle corresponds to a circular arc on the unit circle with length \(\frac{\pi}{6} ?\)
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Chapter 4: Problem 28
What angle corresponds to a circular arc on the unit circle with length \(\frac{\pi}{6} ?\)
These are the key concepts you need to understand to accurately answer the question.
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In Exercises 5-38, find exact expressions for the indicated quantities, given that $$\cos \frac{\pi}{12}=\frac{\sqrt{2+\sqrt{3}}}{2} \text { and } \sin \frac{\pi}{8}=\frac{\sqrt{2-\sqrt{2}}}{2}$$ [These values for \(\cos \frac{\pi}{12}\) and \(\sin \frac{\pi}{8}\) will be derived in Examples 3 and 4 in Section 5.5.] \(\tan \frac{\pi}{12}\)
The next two exercises emphasize that \(\cos ^{2} \theta\) does not ?qual \(\cos \left(\theta^{2}\right)\) For \(\theta=7^{\circ},\) evaluate each of the following: (a) \(\cos ^{2} \theta\) (b) \(\cos \left(\theta^{2}\right)\)
Show that $$\sin ^{2} \theta=\frac{\tan ^{2} \theta}{1+\tan ^{2} \theta}$$ for all \(\theta\) except odd multiples of \(\frac{\pi}{2}\).
Find the four smallest positive numbers \(\theta\) such that \(\cos \theta=-1\).
Show that $$\cos (\pi-\theta)=-\cos \theta$$ for every angle \(\theta\).
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