Chapter 4: Problem 84
Show that $$\cos (\pi-\theta)=-\cos \theta$$ for every angle \(\theta\).
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Chapter 4: Problem 84
Show that $$\cos (\pi-\theta)=-\cos \theta$$ for every angle \(\theta\).
These are the key concepts you need to understand to accurately answer the question.
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In Exercises 5-38, find exact expressions for the indicated quantities, given that $$\cos \frac{\pi}{12}=\frac{\sqrt{2+\sqrt{3}}}{2} \text { and } \sin \frac{\pi}{8}=\frac{\sqrt{2-\sqrt{2}}}{2}$$ [These values for \(\cos \frac{\pi}{12}\) and \(\sin \frac{\pi}{8}\) will be derived in Examples 3 and 4 in Section 5.5.] \(\cos \left(-\frac{\pi}{8}\right)\)
Show that $$\tan \left(\theta+\frac{\pi}{2}\right)=-\frac{1}{\tan \theta}$$ for every angle \(\theta\) that is not an integer multiple of \(\frac{\pi}{2}\). Interpret this result in terms of the characterization of the slopes of perpendicular lines.
The next two exercises emphasize that \(\sin ^{2} \theta\) does not ?qual \(\sin \left(\theta^{2}\right)\). For \(\theta=4\) radians, evaluate each of the following: (a) \(\sin ^{2} \theta\) (b) \(\sin \left(\theta^{2}\right)\)
Find exact expressions for the indicated quantities. \(\tan (u+8 \pi)\)
A surveyor wishes to measure the distance between points \(A\) and \(B\), but buildings between \(A\) and \(B\) prevent a direct measurement. Thus the surveyor moves 50 meters perpendicular to the line \(A B\) to the point \(C\) and measures that angle \(B C A\) is \(87^{\circ} .\) What is the distance between the points \(A\) and \(B ?\)
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