/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Use a graphing utility to graph ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a graphing utility to graph and solve the equation. Approximate the result to three decimal places. Verify your result algebraically. $$6 e^{1-x}=25$$

Short Answer

Expert verified
The approximate solution to the equation \(6e^{1-x} = 25\) is \(x = 0.471\).

Step by step solution

01

Graph the Equation

First, input the equation \(6e^{1-x}=25\) into a graphing utility, and graph it. The x-intercept of this graph will give the solution to the equation, as that is the point where the graph crosses the x-axis, or in other words, where the equation equals zero.
02

Approximate the Solution

The graph shows the function crossing the x-axis at approximately \(x=0.471\). This is the approximate solution to the equation.
03

Verify the Solution Algebraically

Next, verify the solution by substituting \(x=0.471\) into the original equation and calculating the resulting value. If the left and right sides of the equation are approximately equal, then the solution is verified. Solve for \(6e^{1-x} = 6e^{1-0.471}\) using a calculator to get approximately 25. This verifies the result.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.