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In Exercises \(37-58,\) use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.) $$\log _{5} \frac{x^{2}}{y^{2} z^{3}}$$

Short Answer

Expert verified
The expression \(\log _{5} \frac{x^{2}}{y^{2} z^{3}}\) simplifies to \(2 \log _{5} (x) - 2 \log _{5} (y) - 3 \log _{5} (z)\).

Step by step solution

01

Identify the type of problem

The expression given is a single log of a quotient. The objective is to break down this expression into a sum, difference, or multiple of logs.
02

Apply the quotient logarithmic property

We will use the property \(\log_b (a / b) = \log_b a - \log_b b\). This will convert the expression \(\log _{5} \frac{x^{2}}{y^{2} z^{3}}\) to \(\log _{5}(x^{2}) - \log _{5}(y^{2} z^{3})\). This property states that the log of a quotient equals the log of the numerator minus the log of the denominator.
03

Apply the power rule of logarithms

The power rule of logarithms allows us to bring down the powers from each term as coefficients. Therefore, the expression simplifies further to \(2 \log _{5} (x) - 2 \log _{5} (y) - 3 \log _{5} (z)\). The power rule states that the logarithm of anything raised to a power is equal to that power times the logarithm of the base.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Properties
Logarithms are mathematical tools that simplify complex multiplication and division operations into more manageable additions and subtractions. Understanding the properties of logarithms is fundamental for solving equations in algebra and calculus. One of the key properties is that logarithms convert the multiplication of variables into a sum of logarithms, such as in the identity \(\log_b(mn) = \log_b(m) + \log_b(n)\). Another property allows logarithms to transform division into subtraction, represented by \(\log_b\left(\frac{m}{n}\right) = \log_b(m) - \log_b(n)\). Additionally, the exponentiation of a variable can be brought down in front as a coefficient, which is known as the power rule \(\log_b(m^n) = n \cdot \log_b(m)\).

These properties make complex algebraic expressions containing logarithms much easier to manipulate and solve. When dealing with logarithms, it's essential to remember that all variables within logarithmic functions must be positive since logarithms of negative numbers or zero are undefined within the real number system.
Quotient Rule for Logarithms
The quotient rule for logarithms is particularly useful when you have a logarithm of a division. This rule states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator, mathematically represented as \(\log_b\left(\frac{m}{n}\right) = \log_b(m) - \log_b(n)\).

For example, if you want to expand \(\log_{5} \frac{x^2}{y^2 z^3}\), you apply the quotient rule to separate the log of the numerator \(x^2\) and the log of the denominator \(y^2 z^3\). This simplifies the problem from dealing with a complex fraction to working with individual terms that are more straightforward to manage.
Power Rule for Logarithms
The power rule for logarithms is a critical property that simplifies calculations involving logarithms of exponential expressions. It allows you to 'bring down' the exponent of a logarithmic argument, transforming it into a coefficient at the front of the logarithm. Mathematically, it is expressed as \(\log_b(m^n) = n \cdot \log_b(m)\).

When expanding an expression like \(\log _{5}(x^{2})\), using the power rule, you can rewrite it as \(2 \log _{5}(x)\). Similarly, for \(\log _{5}(y^{2} z^{3})\), it becomes \(2 \log _{5}(y) + 3 \log _{5}(z)\), simplifying the original logarithmic expression into a linear combination of logs that are much easier to work with in many algebraic contexts.
Logarithm Expansion
Logarithm expansion involves breaking down a complex logarithmic expression into simpler parts using the properties of logarithms. This technique is especially useful when you encounter a log with an exponent or a quotient, as it allows you to express the log as a sum or difference of logs.

For instance, with the expression \(\log _{5} \frac{x^{2}}{y^{2} z^{3}}\), you would first apply the quotient rule to get \(\log _{5}(x^{2}) - \log _{5}(y^{2} z^{3})\). You would then use the power rule to break down each term further, resulting in \(2 \log _{5} (x) - 2 \log _{5} (y) - 3 \log _{5} (z)\). This expansion helps in various ways, such as solving for variables within the logarithms or comparing two logarithmic expressions. It's a process that is essential for students to master for proficiency in algebra and higher-level math courses.

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Most popular questions from this chapter

Data Analysis The table shows the time \(t\) (in seconds) required for a car to attain a speed of \(s\) miles per hour from a standing start. $$\begin{array}{|c|c|} \hline \text { Speed, S } & \text { Time, t } \\ \hline 30 & 3.4 \\ 40 & 5.0 \\ 50 & 7.0 \\ 60 & 9.3 \\ 70 & 12.0 \\ 80 & 15.8 \\ 90 & 20.0 \\ \hline \end{array}$$ Two models for these data are as follows. \(t_{1}=40.757+0.556 s-15.817 \ln s\) \(t_{2}=1.2259+0.0023 s^{2}\) (a) Use the regression feature of a graphing utility to find a linear model \(t_{3}\) and an exponential model \(t_{4}\) for the data. (b) Use the graphing utility to graph the data and each model in the same viewing window. (c) Create a table comparing the data with estimates obtained from each model. (d) Use the results of part (c) to find the sum of the absolute values of the differences between the data and the estimated values given by each model. Based on the four sums, which model do you think best fits the data? Explain.

Solve the equation algebraically. Round your result to three decimal places. Verify your answer using a graphing utility. $$2 x \ln x+x=0$$

Use a graphing utility to graph and solve the equation. Approximate the result to three decimal places. Verify your result algebraically. $$6 e^{1-x}=25$$

Writing a Natural Logarithmic Equation In Exercises \(53-56,\) write the exponential equation in logarithmic form. $$e^{1 / 2}=1.6487 \ldots$$

Using the One-to-One Property In Exercises \(73-76,\) use the One-to-One Property to solve the equation for \(x\). $$\ln (x+4)=\ln 12$

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