/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Use a graphing utility to constr... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a graphing utility to construct a table of values for the function. Then sketch the graph of the function. $$f(x)=e^{-x}$$

Short Answer

Expert verified
The graph of the function \(f(x) = e^{-x}\) is a curve that starts at a high point when x is negative, touches the point (0,1), and decreases as x becomes positive, approaching but never reaching the x-axis.

Step by step solution

01

Construct a table of values

Decide on a range of x values and then calculate the corresponding y values by using the function \(f(x)=e^{-x}\). For example, for the x values -2, -1, 0, 1, 2, relevant y values will need to be calculated.
02

Evaluate the function

Using the function, evaluate each x value from the table. For example, for \(x = -2\), the y value is \(e^{2}\), for \(x = -1\) it is \(e\), for \(x = 0\) it is 1, for \(x = 1\) it is \(e^{-1}\), and for \(x = 2\) it is \(e^{-2}\).
03

Create the graph

Draw a graph and label the x and y axes. Plot each point from the table (each pair of x and y values). Connect the points with a smooth curve to form the graph of the function \(f(x) = e^{-x}\). The graph will show that as x increases, y decreases and as x decrease, y increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constructing a Table of Values
When graphing functions like the exponential decay function f(x) = e^{-x}, creating a table of values is a critical first step. Consider it the foundation on which your graph is built. To start, choose a range of x-values that will adequately show the behavior of the function. A good strategy is to include both negative and positive x-values; this helps to illustrate how the function behaves in different regions.

Using our sample function, calculate the corresponding y-values by substituting the x values into the function. This will yield the output for your table. For instance, when x = 0, f(x) equals 1, because e^0 is always 1. This level of detail helps demystify complex functions and provides a clearer overview before the graphing stage.
Exponential Decay

Exponential decay describes the process where a quantity decreases at a rate proportional to its current value. In the case of the function f(x) = e^{-x}, the base of the exponent (e) is a constant approximately equal to 2.71828, often referred to as Euler's number, a fundamental constant in mathematics. As x increases, e^{-x} gets smaller, hence why we use the term 'decay' rather than 'growth'.

Exponential decay functions are an integral part of many real-life scenarios, such as radioactive decay, cooling of a warm object, or depreciation of assets. Understanding how to graph these functions not only strengthens mathematical skills but also offers insights into these practical phenomena.

Graphing Utilities

Graphing utilities, such as calculators or computer software, are invaluable tools when working with complex functions. They allow for quick and precise calculations of values, which might be cumbersome to do by hand. When constructing a table of values for f(x) = e^{-x}, a graphing utility can instantly generate the needed y-values for a range of x-values, saving time and reducing the likelihood of errors.

Moreover, many graphing utilities come with features to directly plot these values, giving students an immediate visual representation of the function. This not only aids in understanding but also in detecting any possible mistakes in calculations.

Sketching Graphs

After constructing your table of values, the next step is to plot those points on a set of axes. Start by drawing a horizontal x-axis and a vertical y-axis, ensuring both are properly labeled and scaled. Then, mark the points from your table onto the graph, paying careful attention to the exact placement according to your table of values.

Connecting these points will result in the graph of the exponential decay function f(x) = e^{-x}. Remember, the points should form a smooth curve that rapidly decreases as x increases, reflecting the 'decay' aspect of the function. Through practice, you'll get better at sketching these graphs and interpreting their shapes and the information they convey.

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Most popular questions from this chapter

Forensics At 8: 30 A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At 9: 00 A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at 11: 00 A.M. the temperature was \(82.8^{\circ} \mathrm{F}\). From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula $$t=-10 \ln \frac{T-70}{98.6-70}$$ where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling. It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F}\).) Use the formula to estimate the time of death of the person.

Let \(f(x)=\log _{a} x\) and \(g(x)=a^{x},\) where \(a>1\) (a) Let \(a=1.2\) and use a graphing utility to graph the two functions in the same viewing window. What do you observe? Approximate any points of intersection of the two graphs. (b) Determine the value(s) of \(a\) for which the two graphs have one point of intersection. (c) Determine the value(s) of \(a\) for which the two graphs have two points of intersection.

Function \(\quad\) Value $$\text { 58. } f(x)=3 \ln x \quad x=0.74$$

A classmate claims that the following are true. (a) \(\ln (u+v)=\ln u+\ln v=\ln (u v)\) (b) \(\ln (u-v)=\ln u-\ln v=\ln \frac{u}{v}\) (c) \((\ln u)^{n}=n(\ln u)=\ln u^{n}\) Discuss how you would demonstrate that these claims are not true.

Solve the equation algebraically. Round your result to three decimal places. Verify your answer using a graphing utility. $$\frac{1+\ln x}{2}=0$$

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