/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Verify the identity. $$\sec ^{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Verify the identity. $$\sec ^{4} x \tan ^{2} x=\left(\tan ^{2} x+\tan ^{4} x\right) \sec ^{2} x$$

Short Answer

Expert verified
The final result \( (\tan^2 x + \tan^4 x)\sec^2 x \) verifies the given identity.

Step by step solution

01

Express sec^4 x in terms of sec^2 x.

We can rewrite \( \sec ^{4} x \) as \( (\sec ^{2} x)^{2} \). This gives us \( (\sec ^{2} x)^{2} \tan ^{2} x \)
02

Use the trigonometric identity sec^2 x = 1 + tan^2 x

We can substitute \( \sec ^{2} x \) with \( 1+ \tan ^{2} x \) in the above expression. This gives us \( (1+ \tan ^{2} x)^{2} \tan ^{2} x \)
03

Expand the square

On expanding \( (1+ \tan ^{2} x)^{2} \) we get \( 1+ 2\tan ^{2} x + \tan ^{4} x \). Thus the expression becomes \( (1+ 2\tan ^{2} x + \tan ^{4} x)\tan ^{2} x \)
04

Distribute \( \tan^2 x \)

Multiply the \( \tan^2 x \) into the parentheses, giving \( \tan^2 x + 2\tan^4 x + \tan^6 x \).
05

Reorganize terms

Reorder the expression to \( \tan^2 x + \tan^4 x + \tan^4 x \).
06

Factor out a sec^2 x

Factor out a \( \sec^2 x = 1+ \tan^2 x \) from the expression, resulting in \( (\tan^2 x + \tan^4 x)\sec^2 x \). This verifies the given identity.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.