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Use a graphing utility to approximate the solutions (to three decimal places) of the equation in the interval \([0,2 \pi)\). $$2 \tan ^{2} x+7 \tan x-15=0$$

Short Answer

Expert verified
The approximate solutions are \(x_1 = 0.931\), \(x_2 = 3.073\), \(x_3 = 4.487\), and \(x_4 = 6.630\), all within the interval \([0,2\pi)\), and to three decimal places.

Step by step solution

01

Rewrite the equation in standard quadratic form

Use the quadratic formula \(x = (-b\pm \sqrt{b^2 - 4ac}) / 2a\), where \(a\), \(b\), and \(c\) are the coefficients of the quadratic equation. Here, our equation can be written as \(2y^2 + 7y - 15 = 0\), where \(y = \tan x\). So, \(a = 2\), \(b = 7\), and \(c = -15\).
02

Find the roots of the equation

Substitute the values of \(a\), \(b\), and \(c\) in the quadratic formula to find the roots \(y_1\) and \(y_2\). We obtain \(y_1 = 1.5\) and \(y_2 = -5\). So, we have two equations \(\tan x = y_1\) and \(\tan x = y_2\), or \(\tan x = 1.5\) and \(\tan x = -5\).
03

Solve for x using the graph

Plot the function \(y = \tan x\) and the values \(y = 1.5\) and \(y = -5\) on a graphing calculator. Check the intervals where the graph intersects with \(y = 1.5\) and \(y = -5\). Those x-values (in the interval \([0,2\pi)\)) will be the solutions of our equation.
04

Approximate to three decimal places

Using the calculator's built-in tools or approximations, find the approximate x-values of these intersections to three decimal places. Each intersection represents a solution to the original equation.

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