/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Solve the logarithmic equation a... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the logarithmic equation algebraically. Approximate the result to three decimal places. $$\ln x=1.6$$

Short Answer

Expert verified
The value of x, when rounded to three decimal places, is approximately \(4.953\)

Step by step solution

01

Isolate x

This is a logarithmic equation where the equation is equal to a constant. To solve for x, the inverse operation of logarithm base 'e' operator, which is exponentiation using base 'e' (i.e., \(e^y\)), needs to be applied. Apply the \(e^y\) operation to both sides of the equation: \[e^{\ln(x)} = e^{1.6}\] The left-hand side simplifies to x, because \(e^{\ln(y)} = y\), which isolates x: \[x = e^{1.6}\]
02

Evaluate the expression

Evaluate \(e^{1.6}\) on a calculator to find the value of x.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Functions
Logarithmic functions are the inverse of exponential functions. In basic terms, if you have an exponential function where a number is raised to a certain power to achieve another number, a logarithmic function tells you the power that the original number needs to be raised to, to get that other number. This concept is best expressed by the equation:
\[ b^y = x \Rightarrow \log_b(x) = y \]
Here, \( b \) is the base of the logarithm, \( y \) is the logarithm (the power), and \( x \) is the result you get when raising \( b \) to the power of \( y \). When you see an equation like \( \ln x = 1.6 \), it involves the natural logarithm, which is a specific type of logarithmic function where the base is \( e \), the Euler's number (approximately equal to 2.718).

To solve logarithmic equations like the given exercise, one must understand the relationship between logarithms and exponentiation. The statement \( \ln x = 1.6 \) signifies that the power you need to raise \( e \) to get \( x \) is 1.6. It's crucial to grasp this connection to correctly approach and solve logarithmic equations.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), has the Euler's number \( e \) as its base, which is an irrational and transcendental number approximately equal to 2.71828. It plays a significant role in various branches of mathematics, especially in solving problems involving growth and decay, such as in finance with compound interest or in biology with population models.

Using the natural logarithm, the equation \( \ln x \) equates to asking, 'To what power must \( e \) be raised to obtain \( x \)?' For the exercise provided, \( \ln x = 1.6 \) simplifies to \( e^{1.6} = x \), which can be evaluated using a calculator. Accordingly, this operation is central to converting from the logarithmic form back to the exponent form, helping us to find explicit values for the variable in question.

It is important to remember that the natural logarithm is the inverse of exponentiation by \( e \); therefore, solving equations with natural logarithms often includes using exponentiation to 'undo' the logarithm and isolate the variable.
Exponentiation
Exponentiation is a mathematical operation involving two numbers, the base and the exponent. The exponent indicates how many times the base is multiplied by itself. For example, \( 3^2 \) means 3 is multiplied by itself twice, giving us 9.

When dealing with logarithms, exponentiation is the process used to 'undo' the logarithm. Since logarithmic functions are the inverse of exponential functions, you can solve a logarithmic equation by raising the base of the logarithm to the power given by the logarithm. This is why, in the exercise solution, exponentiation is used to isolate \( x \) on one side by applying \( e \) to the power of 1.6, denoted as \( e^{1.6} \).

In our exercise, we see that to find the value of \( x \), we must exponentiate the base \( e \) to the power of the given number. Calculator assists in finding the numerical value of such expressions, which in this case provides the approximate value of \( x \). It's essential for students to become comfortable with exponentiation as it is a fundamental operation that often appears in algebra and higher-level mathematics.

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Most popular questions from this chapter

A sport utility vehicle that costs $$\$ 23,300$$ new has a book value of $$\$ 12,500$$ after 2 years. (a) Find the linear model \(V=m t+b\). (b) Find the exponential model \(V=a e^{k t}\) (c) Use a graphing utility to graph the two models in the same viewing window. Which model depreciates faster in the first 2 years? (d) Find the book values of the vehicle after 1 year and after 3 years using each model. (e) Explain the advantages and disadvantages of using each model to a buyer and a seller.

Is it possible for a logarithmic equation to have more than one extraneous solution? Explain.

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A laptop computer that costs $$\$ 1150$$ new has a book value of $$\$ 550$$ after 2 years. (a) Find the linear model \(V=m t+b\). (b) Find the exponential model \(V=a e^{k t}\) (c) Use a graphing utility to graph the two models in the same viewing window. Which model depreciates faster in the first 2 years? (d) Find the book values of the computer after 1 year and after 3 years using each model. (e) Explain the advantages and disadvantages of using each model to a buyer and a seller.

Carbon 14 dating assumes that the carbon dioxide on Earth today has the same radioactive content as it did centuries ago. If this is true, the amount of \({ }^{14} \mathrm{C}\) absorbed by a tree that grew several centuries ago should be the same as the amount of \({ }^{14} \mathrm{C}\) absorbed by a tree growing today. A piece of ancient charcoal contains only \(15 \%\) as much radioactive carbon as a piece of modern charcoal. How long ago was the tree burned to make the ancient charcoal if the half-life of \({ }^{14} \mathrm{C}\) is 5715 years?

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