/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Write the exponential equation i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write the exponential equation in logarithmic form. $$e^{x}=4$$

Short Answer

Expert verified
The logarithmic form of the equation \(e^{x}=4\) is \( \log_e 4 = x \), which is typically written as \( \ln 4 = x \).

Step by step solution

01

Identify the base, exponent and result

In the given equation, \(e^{x}=4\), e is the base, x is the exponent, and 4 is the result.
02

Write in logarithmic form

Using the conversion formula from exponential to logarithmic form, the equation \(e^{x}=4\) can be written as \( \log_e 4 = x \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Equations
Exponential equations are equations in which a constant base is raised to a variable exponent. These can naturally arise in contexts involving growth or decay, such as population dynamics, finance for interest calculations, or physics for radioactive decay. An exponential equation generally takes the form of \( a^{x} = b \), where:
  • \(a\) is the base,
  • \(x\) is the exponent (variable),
  • \(b\) is the result.
What makes these equations interesting and essential is their ability to model real-world phenomena that change multiplicatively. Let’s take a closer look at an example: the equation \( e^{x} = 4 \). In this specific equation:
  • The base \(e\) is a constant approximately equal to 2.718 and is known as Euler's number.
  • The variable \(x\) represents the power to which the base is raised.
  • The result \(4\) is what the expression equals when \(e\) is raised to the power of \(x\).
To solve exponential equations like this, we often use logarithms, as they provide a convenient method to deal with the variable exponent.
Logarithms
Logarithms are mathematical operations that are the inverse of exponentiation. Instead of answering what power a number must be raised to get another number (as in exponents), logarithms tell you that power directly. The logarithm can be simply defined as: if \(a^{x} = b\), then \( \log_a b = x \). Here:
  • \(a\) is the base of the logarithm and must be greater than zero and not equal to one.
  • \(b\) is the result of the exponential expression.
  • \(x\) is the exponent we want to find.
Logarithms are especially useful in solving equations involving exponentials because they "bring down" the variable from the exponent position to a linear form, which is easier to solve. For example, in the equation \( e^{x} = 4 \), converting to logarithmic form gives us \( \log_e 4 = x \), shedding light on the value of \(x\) without solving exponentially.
Conversion from Exponential to Logarithmic Form
The conversion from exponential form to logarithmic form is an essential mathematical skill, crucial for simplifying and solving equations involving exponentials. The general rule for converting is: if you have an equation \(a^{x} = b\), you can write it as \( \log_a b = x \). This allows us to express the equation in a form where the unknown is not in the exponent, thus making it easier to handle.For the example \( e^{x} = 4 \), we converted it to its logarithmic form as \( \log_e 4 = x \). This conversion highlights the relationship:
  • Base \(e\) becomes the base of the logarithm.
  • Result \(4\) turns into the arguement of the logarithm.
  • Exponent \(x\) becomes the result of the logarithmic operation.
Understanding this process not only helps in mathematics but also in other scientific fields, wherever exponential growth and decay are encountered. By converting to a logarithmic form, we bring a powerful tool to solve for unknowns efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use a graphing utility to graph and solve the equation. Approximate the result to three decimal places. Verify your result algebraically. $$3-\ln x=0$$

A logistic curve is also called a ________ curve.

An exponential growth model has the form ________ and an exponential decay model has the form ________.

A $$\$ 120,000$$ home mortgage for 30 years at \(7 \frac{1}{2} \%\) has a monthly payment of $$\$ 839.06 .$$ Part of the monthly payment is paid toward the interest charge on the unpaid balance, and the remainder of the payment is used to reduce the principal. The amount that is paid toward the interest is \(u=M-\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t}\) and the amount that is paid toward the reduction of the principal is \(v=\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t}\) In these formulas, \(P\) is the size of the mortgage, \(r\) is the interest rate, \(M\) is the monthly payment, and \(t\) is the time (in years). (a) Use a graphing utility to graph each function in the same viewing window. (The viewing window should show all 30 years of mortgage payments.) (b) In the early years of the mortgage, is the larger part of the monthly payment paid toward the interest or the principal? Approximate the time when the monthly payment is evenly divided between interest and principal reduction. (c) Repeat parts (a) and (b) for a repayment period of 20 years \((M=\$ 966.71) .\) What can you conclude?

If $$\$ 1$$ is invested in an account over a 10-year period, the amount in the account, where \(t\) represents the time in years, is given by \(A=1+0.075 \llbracket t \rrbracket\) or \(A=e^{0.07 t}\) depending on whether the account pays simple interest at \(7 \frac{1}{2} \%\) or continuous compound interest at \(7 \%\). Graph each function on the same set of axes. Which grows at a higher rate? (Remember that \(\llbracket t \rrbracket\) is the greatest integer function discussed in Section 1.6.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.