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Solve the exponential equation algebraically. Approximate the result to three decimal places. $$6^{x}+10=47$$

Short Answer

Expert verified
The solution to the equation is \(x \approx 2.530\)

Step by step solution

01

Isolate the Exponential Term

The first step is to isolate the exponential term. This is done by subtracting 10 from both sides of the equation. So the equation becomes \(6^{x}=47-10\), which simplifies to \(6^{x}=37\)
02

Apply Logarithm Rules to Isolate the Variable x

In exponential equations, to solve for the variable in the exponent, applying a logarithm to both sides of the equation is a useful strategy. Here, the natural log (ln) can be applied to both sides of the equation, resulting in \(\ln(6^{x}) = \ln(37)\). According to the properties of logarithms, namely the power rule, \(x\) in the equation becomes a coefficient. This gives the equation \(x \cdot \ln(6) = \ln(37)\)
03

Solve for x

Finally, to solve for x, divide both sides of the equation by \(\ln(6)\). The equation becomes \(x = \frac{\ln(37)}{\ln(6)}\) Swipe a calculator to compute this value. This yields \(x \approx 2.530\) when rounded to three decimal places

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