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Find \(a\) and \(b\) if the graph of \(y=a x^{2}+b x^{3}\) is symmetric with respect to (a) the \(y\) -axis and (b) the origin. (There are many correct answers.)

Short Answer

Expert verified
For the function to be symmetric with respect to the y-axis, we need \(b = 0\), therefore any pair \((a, 0)\) where \(a\) is any real number is a solution. For the function to be symmetric with respect to the origin, we need \(a = 0\), hence any pair \((0, b)\), where \(b\) is any real number is a solution.

Step by step solution

01

Determine Symmetry with Respect to the Y-Axis

To find the values of \(a\) and \(b\) for which the function \(y = ax^2+bx^3\) is symmetric about the y-axis, use the constraint that an even function must satisfy \(f(-x)=f(x)\). Substituting this into the equation yields \(a(-x)^2 + b(-x)^3 = ax^2 + bx^3\). This simplifies to \(ax^2 - bx^3 = ax^2 + bx^3\). The only way for this equation to hold for all \(x\) is if \(b = 0\). Therefore, all pairs \((a, 0)\) will make the function symmetric with respect to the y-axis.
02

Determine Symmetry with Respect to the Origin

Next, to find the values of \(a\) and \(b\) for which the graph is symmetric about the origin, use the constraint for odd functions, specifically \(f(-x) = -f(x)\). Substituting this into the equation results in \(a(-x)^2 + b(-x)^3 = -(ax^2 + bx^3)\). Simplifying this expression gives \(ax^2 - bx^3 = -ax^2 - bx^3\), which only holds for all \(x\) if \(a = 0\). So, the pairs \((0, b)\) will make the function symmetric with respect to the origin.

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