/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 104 Determine whether the statement ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the statement is true or false. Justify your answer. If the inverse function of \(f\) exists and the graph of \(f \mathrm{~h}\) a \(y\) -intercept, then the \(y\) -intercept of \(f\) is an \(x\) -intercep of \(f^{-1}\)

Short Answer

Expert verified
The statement is True. An y-intercept on a function translates into an x-intercept on its inverse function (assuming the inverse exists).

Step by step solution

01

Notate the statement

First, identify the statement presented: if \( f \) is a function that has an inverse and \( f \) has a \( y \)-intercept, this intercept turns into an \( x \)-intercept of \( f^{-1} \). This suggests that if \( (a,0) \) is a \( y \)-intercept of \( f \), then \( (0,a) \) should be an \( x \)-intercept of \( f^{-1} \).
02

Recall properties of inverse functions

The graph of an inverse function \( f^{-1} \) is a reflection of the graph of \( f \) over the line \( y = x \). Therefore, if \( (a, 0) \) is a point on the graph of \( f \), then its mirror image \( (0, a) \) should be a point on the graph of \( f^{-1} \).
03

Link intercepts to the original statement

Because \( y \)-intercepts are points on the \( y \)-axis where \( x = 0 \), the mirrored points on the \( x \)-axis become \( x \)-intercepts where \( y = 0 \). Therefore, \( (a,0) \) being a \( y \)-intercept of \( f \) indeed results in \( (0,a) \) being an \( x \)-intercept of \( f^{-1} \).
04

Conclusion

After examining these facts, it's clear that the original statement is True. The \( y \)-intercepts of a function translate as \( x \)-intercepts for the function's inverse, if the inverse exists.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Inverse Functions
Understanding the properties of inverse functions is crucial for grasping the relationship between a function and its inverse. When a function f has an inverse, denoted by f-1, there are specific characteristics that this inverse will possess. One of the key properties is that the domain of f becomes the range of f-1, and vice versa. This implies that all x-values where f is defined are y-values for f-1.

Another vital property is the 'horizontal line test.' This test tells us that if any horizontal line intersects the graph of a function f at more than one point, the function does not have an inverse because it is not one-to-one. This is crucial because only one-to-one functions, which pass the horizontal line test, have inverses that are also functions.

Moreover, the inverse function f-1 undoes the operations of f. For any value x within the domain of f, applying f and then f-1 (or vice versa) will return x. That is, f-1(f(x)) = x and f(f-1(y)) = y. These properties form the foundation for understanding how intercepts and inverse functions relate to each other.
Intercepts and Inverse Functions
The relationship between intercepts of a function and its inverse is a direct application of the properties of inverse functions. An intercept represents where a graph crosses an axis, which occurs at the x-axis for an x-intercept and the y-axis for a y-intercept. To make sense of this in the context of inverses, consider that the intercepts on a graph of f correspond to particular values in the domain and range of f.

For a function f, a y-intercept is a point where the graph crosses the y-axis, which occurs when x equals zero. Given that inverse functions swap the roles of inputs (x-values) and outputs (y-values), a y-intercept of (0, b) on f becomes an x-intercept on f-1 at the point (b, 0). Consequently, the x-intercepts of f can also be understood as y-intercepts of f-1 under the same reasoning.

By understanding this inverse relationship between intercepts, students can better predict and recognize the behavior of inverse functions in graphical form. This understanding is an integral component in solving many algebraic and calculus problems involving functions and their inverses.
Reflection Over the Line y=x
One of the most graphical representations of an inverse function is its reflection over the line y = x. When the graph of a function f is reflected across this line, each point on the graph of f maps to a corresponding point on the graph of its inverse f-1. This visual symmetry is not merely a conceptual tool; it provides a way to predict and verify the points on the inverse function.

If we take any point (a, b) on the graph of f, we find its mirror across the line y = x, resulting in point (b, a) on the graph of f-1. Therefore, reflection over y = x swaps the x and y coordinates of points on the graph of f, which is consistent with the definition of inverse functions switching inputs and outputs.

For example, if the original function has a point (3, 4), reflecting this point across the line y = x will locate that point at (4, 3) on the inverse function's graph. This reflection property is a powerful tool for graphing inverse functions and understanding their behavior relative to the original function.

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Most popular questions from this chapter

Use the functions given by \(f(x)=\frac{1}{8} x-3\) and \(g(x)=x^{3}\) to find the indicated value or function. $$ \left(g^{-1} \circ g^{-1}\right)(-4) $$

Determine whether the function has an inverse function. If it does, find the inverse function. $$ f(x)=\sqrt{2 x+3} $$

The direct variation model \(y=k x^{n}\) can be described as " \(y\) varies directly as the \(n\) th power of \(x\)," or "y is _____ _____to the \(n\) th power of \(x.\) "

Use the given value of \(k\) to complete the table for the direct variation model $$y=k x^{2}$$ Plot the points on a rectangular coordinate system. $$\begin{array}{|l|l|l|l|l|l|} \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y=k x^{2} & & & & & \\ \hline \end{array}$$ $$ k=\frac{1}{2} $$

The total sales (in billions of dollars) for CocaCola Enterprises from 2000 through 2007 are listed below. (Source: Coca-Cola Enterprises, Inc.) $$\begin{array}{llll} 2000 & 14.750 & 2004 & 18.185 \\ 2001 & 15.700 & 2005 & 18.706 \\ 2002 & 16.899 & 2006 & 19.804 \\ 2003 & 17.330 & 2007 & 20.936 \end{array}$$ (a) Sketch a scatter plot of the data. Let \(y\) represent the total revenue (in billions of dollars) and let \(t=0\) represent 2000 . (b) Use a straightedge to sketch the best-fitting line through the points and find an equation of the line. (c) Use the regression feature of a graphing utility to find the least squares regression line that fits the data. (d) Compare the linear model you found in part (b) with the linear model given by the graphing utility in part (c). (e) Use the models from parts (b) and (c) to estimate the sales of Coca-Cola Enterprises in 2008 . (f) Use your school's library, the Internet, or some other reference source to analyze the accuracy of the estimate in part (e).

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