/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Use the given value of \(k\) to ... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the given value of \(k\) to complete the table for the direct variation model $$y=k x^{2}$$ Plot the points on a rectangular coordinate system. $$\begin{array}{|l|l|l|l|l|l|} \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y=k x^{2} & & & & & \\ \hline \end{array}$$ $$ k=\frac{1}{2} $$

Short Answer

Expert verified
The completed table is :\n \[ \begin{array}{|l|l|l|l|l|l|} \ \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y=\frac{1}{2}x^2 & 2 & 8 & 18 & 32 & 50 \\ \hline \ \end{array} \]\nPoints plotted on the coordinate system are \((2, 2), (4, 8), (6, 18), (8, 32), and (10, 50)\)

Step by step solution

01

Substituting the value of \(k\) in the equation

Replace \(k\) in the equation \(y=kx^{2}\) with \(\frac{1}{2}\) to get \(y=\frac{1}{2}x^{2}\)
02

Filling in the table

For each \(x\) value in the table, substitute \(x\) into the equation from step 1 and compute the value of \(y\). The values are as follows:\nFor \(x=2\), \(y=\frac{1}{2}(2^2)=2\)\nFor \(x=4\), \(y=\frac{1}{2}(4^2)=8\)\nFor \(x=6\), \(y=\frac{1}{2}(6^2)=18\)\nFor \(x=8\), \(y=\frac{1}{2}(8^2)=32\)\nFor \(x=10\), \(y=\frac{1}{2}(10^2)=50\)\n
03

Plotting the points

Plot the points \((2, 2), (4, 8), (6, 18), (8, 32), and (10, 50)\) on a rectangular coordinate system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular Coordinate System
When you're looking at a graph, you're often seeing what's called a rectangular coordinate system, which is also known as a Cartesian coordinate system. Imagine it as a grid with two perpendicular lines, one running from left to right (the x-axis) and the other running from top to bottom (the y-axis). These axes intersect at a point called the origin, denoted by coordinates (0, 0).

Each point on the grid is determined by an ordered pair of numbers, written as \( (x, y) \), where \( x \) is the value on the horizontal axis and \( y \) is the value on the vertical axis. For example, the coordinate (3, 4) means you move 3 units to the right along the x-axis and 4 units up along the y-axis. The rectangular coordinate system allows us to plot points, lines, and curves to represent relationships between variables.
Quadratic Function
A quadratic function is a type of polynomial represented by the equation \( y = ax^2 + bx + c \), where \( a \), \( b \) and \( c \) are constants, and \( a \eq 0 \). It's called 'quadratic' because the highest exponent of the variable x is 2. The graph of a quadratic function is a curve called a parabola. Parabolas have unique shapes and they open either upwards or downwards, depending on the sign of the coefficient \( a \).

As seen in our exercise, when the equation is \( y = \frac{1}{2}x^2 \), this represents a simplified quadratic function where \( a \) is \( \frac{1}{2} \), and \( b \) and \( c \) are both 0. The graph of this function is a parabola that opens upwards since \( \frac{1}{2} \) is positive. As the value of \( x \) increases, the value of \( y \) grows quadratically, meaning it doesn't just double, it squares and is then halved, as indicated by our specific function.
Plotting Points
The task of plotting points is fundamental to graphically representing mathematical relationships. Each calculated pair \( (x, y) \) from your equation corresponds to a single point on the graph. To plot a point, you start at the origin (0, 0), move \( x \) units along the x-axis in the direction that corresponds to the sign of \( x \), and then move \( y \) units parallel to the y-axis, again in the direction given by the sign of \( y \).

After computing the \( y \) values in our table using the quadratic function \( y = \frac{1}{2}x^2 \) for each \( x \) value, we get a set of points. For example, with \( x = 2 \) we calculate \( y = 2 \) and plot the point (2, 2) by moving 2 units to the right and 2 units up from the origin. For all our computed points, we follow this process. When connected, these plotted points illustrate the shape of the quadratic function's graph on the rectangular coordinate system.

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Most popular questions from this chapter

An \(r\) -value of a set of data, also called a _____ _____ ,gives a measure of how well a model fits a set of data.

Prove that if \(f\) and \(g\) are one-to-one functions, then \((f \circ g)^{-1}(x)=\left(g^{-1} \circ f^{-1}\right)(x) .\)

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Determine whether the function has an inverse function. If it does, find the inverse function. $$ f(x)=\left\\{\begin{array}{ll} -x, & x \leq 0 \\ x^{2}-3 x, & x>0 \end{array}\right. $$

The total sales (in billions of dollars) for CocaCola Enterprises from 2000 through 2007 are listed below. (Source: Coca-Cola Enterprises, Inc.) $$\begin{array}{llll} 2000 & 14.750 & 2004 & 18.185 \\ 2001 & 15.700 & 2005 & 18.706 \\ 2002 & 16.899 & 2006 & 19.804 \\ 2003 & 17.330 & 2007 & 20.936 \end{array}$$ (a) Sketch a scatter plot of the data. Let \(y\) represent the total revenue (in billions of dollars) and let \(t=0\) represent 2000 . (b) Use a straightedge to sketch the best-fitting line through the points and find an equation of the line. (c) Use the regression feature of a graphing utility to find the least squares regression line that fits the data. (d) Compare the linear model you found in part (b) with the linear model given by the graphing utility in part (c). (e) Use the models from parts (b) and (c) to estimate the sales of Coca-Cola Enterprises in 2008 . (f) Use your school's library, the Internet, or some other reference source to analyze the accuracy of the estimate in part (e).

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