/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Evaluate the function at each sp... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the function at each specified value of the independent variable and simplify. \(g(t)=4 t^{2}-3 t+5\) (a) \(g(2)\) (b) \(g(t-2)\) (c) \(g(t)-g(2)\)

Short Answer

Expert verified
The short answers after simplification are \(g(2) = 11\), \(g(t-2) = 4t^{2} - 11t + 11\), and \(g(t) - g(2) = 4t^{2} - 3t + 5 - 11 = 4t^{2} - 3t - 6\).

Step by step solution

01

Evaluate the function \(g(2)\)

To evaluate the function at \(g(2)\), substitute \(t = 2\) into the function. Then \(g(2)=4 * 2^{2} - 3 * 2 + 5\). Simplify it to get the outcome.
02

Evaluate the function \(g(t-2)\)

To evaluate the function at \(g(t-2)\), substitute \(t-2\) in place of \(t\) into the function. So, \(g(t-2) = 4 * (t-2)^{2} - 3 * (t-2) + 5\). This also requires further simplification.
03

Evaluate the function \(g(t)-g(2)\)

This is a composite operation. First, find \(g(t)\) and \(g(2)\) separately. We know from step 1 that \(g(2)\) is a specific numeric value. \(g(t)\) is the original function. Then, just subtract \(g(2)\) from \(g(t)\) to get the result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Variable
In mathematics, the concept of an independent variable is paramount when studying functions. An independent variable is a value that can be changed or varied, often denoted as 'x' or 't' in algebraic equations. In terms of functions, it's the input that determines the output, which is also known as the dependent variable. For example, in the function g(t) = 4t^2 - 3t + 5, 't' acts as the independent variable. When evaluating a function like g(2) or g(t-2), we are effectively replacing the independent variable with a specific value or expression to compute the corresponding output.

In the exercise provided, evaluating the function g(2) involved substituting the independent variable 't' with the number 2. This substitution method allows us to find the value of the function at specific points, giving us insight into the behavior of the function. For students, mastering the concept of independent variables is essential for understanding how functions work and how to manipulate them for different scenarios.
Quadratic Functions
Quadratic functions are a special type of polynomial function with a degree of two, which means the highest power of the independent variable is squared. The standard form of a quadratic function is f(x) = ax^2 + bx + c, where 'a', 'b', and 'c' are constants, and 'x' represents the independent variable. The quadratic function provided in the exercise, g(t) = 4t^2 - 3t + 5, showcases the typical features of parabolas, such as opening upwards or downwards, having a vertex, and possibly intersecting the x-axis at zero, one or two points.

Students should learn to recognize the shape and components of quadratic functions, as these are fundamental in various areas of mathematics and applied sciences. Understanding how to evaluate quadratic functions, as demonstrated in the steps for g(2) and g(t-2), is especially useful in plotting their graphs and finding important features like the vertex and axis of symmetry. Knowledge of how the coefficients 'a', 'b', and 'c' affect the graph's shape helps students in graphing and interpreting quadratic functions.
Function Simplification
Function simplification is a valuable skill in algebra that involves reducing expressions to their simplest form. The objective is to make the expressions more understandable and easier to work with, especially when solving problems. Simplification can involve expanding brackets, combining like terms, and eliminating any unnecessary parts of the expression that don't change its value.

When evaluating a function for a given value, as seen in step 2 with g(t-2), simplification includes squaring the binomial and then distributing the resulting terms. For instance, 4(t-2)^2 must be expanded before the entire expression can be simplified. Moreover, when computing something like g(t) - g(2) from step 3, simplification not only helps in finding the actual function difference but also in understanding how functions change with different inputs. Simplifying expressions and functions allows students to tackle more complex problems by breaking them down into more manageable parts.

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Most popular questions from this chapter

Determine whether the statement is true or false. Justify your answer. If the inverse function of \(f\) exists and the graph of \(f \mathrm{~h}\) a \(y\) -intercept, then the \(y\) -intercept of \(f\) is an \(x\) -intercep of \(f^{-1}\)

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Determine whether the variation model is of the form \(y=k x\) or \(y=k / x,\) and find \(k .\) Then write \(a\) model that relates \(y\) and \(x\). $$ \begin{array}{|c|c|c|c|c|c|} \hline x & 5 & 10 & 15 & 20 & 25 \\ \hline y & 24 & 12 & 8 & 6 & \frac{24}{5} \\ \hline \end{array} $$

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