/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Use the Binomial Theorem to expa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the Binomial Theorem to expand and simplify the expression. $$(2 x+y)^{3}$$

Short Answer

Expert verified
The expanded and simplified form of the expression \((2x+y)^3\) using the binomial theorem is \(8x^3 + 12x^2*y + 6x*y^2 + y^3\).

Step by step solution

01

Utilizing the Binomial Theorem

The binomial theorem states \((a+b)^n=\sum_{k=0}^{n} {n\choose k}a^{n-k}b^k\). Apply this theorem to our expression \((2x+y)^3\), here 'a' is \(2x\), 'b' is \(y\) and 'n' is \(3\). Utilize this formula to expand and simplify the expression.
02

Expanding the expression

Following the formula, we will get the following terms: When \(k=0\), we get \({3\choose 0}(2x)^{3-0}y^0 = (2x)^3 = 8x^3\), When \(k=1\), we get \({3\choose 1}(2x)^{3-1}y^1 = 3*(2x)^2*y = 12x^2*y\), When \(k=2\), we get \({3\choose 2}(2x)^{3-2}y^2=3*(2x)*y^2 = 6x*y^2\), When \(k=3\), we get \({3\choose 3}(2x)^{3-3}y^3 = y^3\).
03

Summing up all terms

Now add all terms. The expanded and simplified version of our given expression is \((2x+y)^3 = 8x^3 + 12x^2*y + 6x*y^2 + y^3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Expansion
In algebra, polynomial expansion is a strategy used to express a polynomial raised to a power in an expanded form, rather than a compact product format. Understanding polynomial expansion is crucial for simplifying expressions and solving algebraic equations efficiently. To expand a polynomial like \[ (2x + y)^3 \]we need to break it down using the Binomial Theorem. This theorem helps us comprehend how to distribute the power across the terms within the parenthesis.Each term of the expansion involves:
  • A binomial coefficient, determined by combinatorics.
  • The powers of each component of the binomial expression.
These coefficients help allocate the appropriate power to the terms, allowing the expression to be expanded systematically. Implementing polynomial expansion enables you to convert complex expressions into simpler, individual terms.
Combinatorics
Combinatorics is a branch of mathematics centered on counting and arrangements. It's crucial in the process of expanding binomials as it determines binomial coefficients. In the expression \[ (a + b)^n \]the coefficient of each term in the expansion is given by \[ {n \choose k} \] which reads as 'n choose k'.Here's how it connects the dots:
  • Binomial coefficients \[ {n \choose k} \] represent the number of ways to choose k elements from a set of n elements.
  • These coefficients reflect how often each term appears in the expansion.
For instance, when expanding \[ (2x + y)^3 \],different values of k (0, 1, 2, 3) produce coefficients (1, 3, 3, 1). These correspond to the expanded expression terms, crafted from choosing elements 0 to 3 times.
Algebraic Simplification
Algebraic simplification is a process that turns a complex, expanded algebraic expression into a simpler, more concise form. It involves combining like terms and performing basic arithmetic operations to make the expression as straightforward as possible.For example, in the context of expanding \[ (2x + y)^3 \],the expansion results in \[ 8x^3 + 12x^2y + 6xy^2 + y^3 \]. This simplified expression:
  • Combines similar types of terms based on their powers and variables.
  • Presents the expression in a manner that's easier to manipulate or understand.
Through algebraic simplification, you gain a clearer, manageable understanding of the polynomial without compromising its integrity or value.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The amounts \(f(t)\) (in billions of dollars) of child support collected in the United States from 2002 through 2009 can be approximated by the model $$f(t)=-0.009 t^{2}+1.05 t+18.0, \quad 2 \leq t \leq 9$$, where \(t\) represents the year, with \(t=2\) corresponding to 2002. (Source: U.S. Department of Health and Human Services). (a) You want to adjust the model so that \(t=2\) corresponds to 2007 rather than \(2002 .\) To do this, you shift the graph of \(f\) five units to the left to obtain \(g(t)=f(t+5) .\) Use binomial coefficients to write \(g(t)\) in standard form. (b) Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. (c) Use the graphs to estimate when the child support collections exceeded \(\$ 25\) billion.

A shipment of 12 microwave ovens contains three defective units. A vending company has ordered four units, and because each has identical packaging, the selection will be random. What is the probability that (a) all four units are good, (b) exactly two units are good, and (c) at least two units are good?

Which two functions have identical graphs, and why? Use a graphing utility to graph the functions in the given order and in the same viewing window. Compare the graphs. (a) \(f(x)=(1-x)^{3}\) (b) \(g(x)=1-x^{3}\) (c) \(h(x)=1+3 x+3 x^{2}+x^{3}\) (d) \(k(x)=1-3 x+3 x^{2}-x^{3}\) (e) \(p(x)=1+3 x-3 x^{2}+x^{3}\)

In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?

Evaluate \(_{n} C_{r}\) using a graphing utility. \(_{20} C_{4}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.