/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 In how many different ways can a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?

Short Answer

Expert verified
The number of ways a jury of 12 people can be randomly selected from a group of 40 people is given by \( C(40,12) \)

Step by step solution

01

Identify n and r

Here, the total number of people (n) is 40 and the number of people to be selected (r) is 12.
02

Apply the combination formula

The combination of 40 people taken 12 at a time can be calculated using the formula: \( C(40,12) = \frac{40!}{12!(40-12)!} \)
03

Calculate the Factorials

Calculate the factorials of 28, 12, and 40.
04

Compute the combination

With all these values, compute the combination.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations
Combinations are a fundamental part of combinatorics and they refer to the selection of objects or people where the arrangement doesn’t matter. Imagine you have a deck of cards and you want to pick three cards. If the specific order of picking those cards is not important, you’re dealing with combinations. This concept is used in various fields, including mathematics, statistics, and even in planning events.

To calculate combinations, you can use the combination formula:
  • Notation: \( C(n, r) \)
  • The formula: \( C(n, r) = \frac{n!}{r!(n-r)!} \)
Here, \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
This equation shows that you're dividing out the permutations of the selected items so that different orders of the same items aren't counted multiple times. In the exercise's context, when you're picking a jury out of 40 people without caring about the order, you apply this formula to find how many unique groups can be made. It's fantastic because it allows you to efficiently calculate large sets without having to list every combination.
Factorials
Factorials are a key mathematical operation, especially in combinatorics. The factorial of a non-negative integer \( n \) is the product of all positive integers less than or equal to \( n \). The notation is \( n! \). For example, \( 4! = 4 \times 3 \times 2 \times 1 = 24 \).
  • Important Values: \( 0! = 1 \) by definition
  • \( 1! = 1 \)
Factorials grow extremely fast. They are used to compute permutations and combinations because they simplify the repeated patterns found in arrangements and selections.
For instance, in calculating combinations such as \( C(40,12) \), you need the factorials of 40, 12, and 28 (since \( 28 = 40 - 12 \)). This operation helps in reducing the complexity of the calculations by avoiding manual computation of each arrangement possibility, hence making things simpler and manageable.
Permutations
Permutations are another core component of combinatorics, and contrary to combinations, they focus on scenarios where order matters. If you’re arranging books on a shelf or planning a sequence of events, permutations will come into play.
The formula for permutations of \( n \) things taken \( r \) at a time is:
  • Notation: \( P(n, r) \)
  • Formula: \( P(n, r) = \frac{n!}{(n-r)!} \)
Here, \( n! \) accounts for all possible orders of the selected items, while \((n-r)!\) cancels out the arrangements beyond what's selected.
While the exercise focuses on combinations, understanding permutations helps to appreciate how specific ordering changes calculations. If, for example, the question asked not about selecting the jury, but ordering the jury in a line, permutations of 40 people selected 12 at a time could be used instead.
Thus, learning the difference between permutations and combinations is crucial for accurately solving problems where the order of selection is a factor!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the number of diagonals of the polygon. (A line segment connecting any two nonadjacent vertices is called a diagonal of the polygon.) Hexagon

Consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure." The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment.The probability of a baseball player getting a hit during any given time at bat is \(\frac{1}{4} .\) To find the probability that the player gets three hits during the next 10 times at bat, evaluate the term $$_{10} C_{3}\left(\frac{1}{4}\right)^{3}\left(\frac{3}{4}\right)^{7}$$, in the expansion of \(\left(\frac{1}{4}+\frac{3}{4}\right)^{10}\).

The table shows the average prices \(f(t)\) (in cents per kilowatt hour) of residential electricity in the United States from 2003 through 2010 . (Source: U.S. Energy Information Administration ).$$\begin{array}{|c|c|}\hline \text { Year } & \text { Abcrage Poids }(10) \\\\\hline 2003 & 8.72 \\\2004 & 8.95 \\\2005 & 9.45 \\\2006 & 10.40 \\\2007 & 10.65 \\\2008 & 11.26 \\\2009 & 11.51 \\\2010 & 11.58 \\\\\hline\end{array}$$.(a) Use the regression feature of a graphing utility to find a cubic model for the data. Let \(t\) represent the year, with \(t=3\) corresponding to 2003 (b) Use the graphing utility to plot the data and the model in the same viewing window. (c) You want to adjust the model so that \(t=3\) corresponds to 2008 rather than \(2003 .\) To do this, you shift the graph of \(f\) five units to the left to obtain \(g(t)=f(t+5) .\) Use binomial coefficients to write \(g(t)\) in standard form. (d) Use the graphing utility to graph \(g\) in the same viewing window as \(f\) (e) Use both models to predict the average price in \(2011 .\) Do you obtain the same answer? (f) Do your answers to part (e) seem reasonable? Explain. (g) What factors do you think may have contributed to the change in the average price?

Find the number of diagonals of the polygon. (A line segment connecting any two nonadjacent vertices is called a diagonal of the polygon.) Decagon (10 sides)

\(A 3 \times 3 \times 3\) cube is made up of 27 unit cubes (a unit cube has a length, width, and height of 1 unit), and only the faces of each cube that are visible are painted blue, as shown in the figure. (a) Complete the table to determine how many unit cubes of the \(3 \times 3 \times 3\) cube have 0 blue faces, 1 blue face, 2 blue faces, and 3 blue faces. $$\begin{array}{|l|l|l|l|l|} \hline \begin{array}{l} \text { Number of } \\ \text { Blue Cube Faces } \end{array} & 0 & 1 & 2 & 3 \\ \hline 3 \times 3 \times 3 & & & & \\ \hline \end{array}$$ (b) Repeat part (a) for a \(4 \times 4 \times 4\) cube, a \(5 \times 5 \times 5\) cube, and a \(6 \times 6 \times 6\) cube. (c) What type of pattern do you observe? (d) Write formulas you could use to repeat part (a) for an \(n \times n \times n\) cube.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.