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Fill in the blanks. You obtain the ________ ________ after multiplying each side of the partial fraction decomposition form by the least common denominator.

Short Answer

Expert verified
You obtain the original rational function after multiplying each side of the partial fraction decomposition form by the least common denominator.

Step by step solution

01

Recall the terminology

In mathematics, when you multiply each side of an equation by the same non-zero value, the equality remains. When it comes to a partial fraction decomposition, the objective is to express a complex fraction as the sum or difference of simpler fractions. Multiplying each side of this by their least common denominator (LCD) simplifies the fraction. The result obtained is the original rational function before it was decomposed into simpler fractions.
02

Fill in the blank

After recalling this concept, the terminology used can be filled in. By multiplying each side of the partial fraction decomposition by the least common denominator, a rational expression in its original form is achieved. Thus, the blanks can be filled as - 'original rational function' or 'original polynomial'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Expression
A rational expression is like a fraction but in a more mathematical sense. It is a ratio of two polynomials, much like how a simple fraction is a ratio of two integers. If you ever saw something that looks like \( \frac{P(x)}{Q(x)} \), where both \(P(x)\) and \(Q(x)\) are polynomials, you’ve met a rational expression!
These expressions are fundamental in algebra because they can represent many realistic scenarios, like speeds, rates, and much more. However, one thing to note is that the denominator polynomial, \(Q(x)\), should not be zero, because division by zero is undefined in mathematics.
When dealing with rational expressions, it's common to perform operations like addition, subtraction, multiplication, or division. In partial fraction decomposition specifically, we take a complex rational expression and express it as a sum of simpler rational expressions.
Overall, understanding rational expressions is key when working with equations and helps in grasping more complex mathematical concepts like those involved in calculus or algebra.
Least Common Denominator
The least common denominator (LCD) is a vital concept whenever you're dealing with fractions of any kind, including rational expressions. Imagine having two fractions like \( \frac{1}{3} \) and \( \frac{1}{4} \). To add them, you first need a common denominator: an equal base for the fractions. The smallest number that both denominators (3 and 4) divide into is 12. So, 12 becomes your least common denominator.
In the world of rational expressions, finding the LCD works similarly. If we have expressions like \( \frac{1}{(x+2)(x-3)} \) and \( \frac{1}{(x-3)(x+1)} \), to add or subtract them, we would use their combined factors to find the LCD: \((x+2)(x-3)(x+1)\).
The process of multiplying each fraction by something that ensures they have this common denominator is what enables simplification. It is crucial in partial fraction decomposition because it allows the complex rational expression to be treated as a sum or difference of fractions with simpler denominators, easing both computation and interpretation.
Original Polynomial
When we talk about the original polynomial, we're referring to the polynomial that was there before any fraction decomposition occurred. In partial fraction decomposition, you often start with a complex rational expression, and by the end, you simplify back to a cleaner, original form.
Think of it like having a big puzzle that can be taken apart and shown as smaller pieces (partial fractions). The completed puzzle is your original polynomial, while the smaller, separate pieces are the decomposed fractions.
This concept is fundamental because it ensures that after you've performed all operations—multiplying by the least common denominator to eliminate fractions—it all boils back down to the beginning. Such understanding not only solidifies mastery of manipulating rational expressions, but it also makes polynomial identities and equivalencies much clearer.
  • By identifying the original polynomial, any student or mathematician can confirm the correctness of their solution in a partial fraction decomposition problem.
  • This reconversion into the original polynomial is a step that usually verifies the entire process.
It's like traveling a complex path but ensuring you always return home safe, giving you the confidence that you've navigated correctly.

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Most popular questions from this chapter

Solve the system of equations for \(u\) and \(v\). While solving for these variables, consider the transcendental functions as constants. (Systems of this type appear in a course in differential equations.) $$\left\\{\begin{array}{l} u \sin x+v \cos x=0 \\ u \cos x-v \sin x=\sec x \end{array}\right.$$

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Write the partial fraction decomposition of the rational expression. Then assign a value to the constant \(a\) to check the result algebraically and graphically. $$\frac{1}{x(x+a)}$$

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