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Find the domain, \(x\) -intercept, and vertical asymptote of the logarithmic function and sketch its graph. $$g(x)=\ln (-x)$$

Short Answer

Expert verified
The domain of the function \(g(x) = \ln(-x)\) is \(x<0\), the x-intercept is \(x=-1\), and the vertical asymptote is \(x=0\). The graph of the function is a reflection of the standard \(\ln(x)\) function in the y-axis, with an x-intercept at \(x=-1\), and it approaches but never crosses the vertical asymptote at \(x=0\) to the left side of the y-axis.

Step by step solution

01

Find the domain of the function

The natural logarithm, \(\ln(x)\), is defined only for \(x>0\). However, our function has a negative sign inside the logarithm, \(\ln(-x)\). The domain of this function is all \(x\) for which \(-x>0\). If we multiply both sides of the inequality by \(-1\), remembering to flip the inequality sign, we get: \(x<0\). So, the domain of the function \(g(x) = \(\ln(-x)\) is all \(x\) less than \(0\).
02

Find the x-intercept

The x-intercept of the function is the \(x\) value when \(g(x) = 0\). We set up the equation \(\ln(-x)=0\) to find the solution for \(x\). The base of the natural logarithm is \(e\), so we rewrite the equation as: \(-x=e^0\). The exponential function of \(0\) is \(1\), so \(-x=1\). Multiplying both sides by \(-1\) gives: \(x=-1\). So the x-intercept of the function is \(x=-1\).
03

Find the vertical asymptote

For the function \(g(x)=\ln(-x)\), the vertical asymptote is the value of \(x\) for which the function is undefined. As established in Step 1, this occurs when \(x=0\). Thus, the vertical asymptote is \(x=0\).
04

Sketch the graph

Using the information from Steps 1-3, begin sketching the graph. Plot the x-intercept at \(x=-1\) and the vertical asymptote at \(x=0\). Since the domain is \(x<0\), only draw the graph to the left of the asymptote. The graph approaches the asymptote but never crosses it. Because of the negative sign in front of the \(x\) in \(\ln(-x)\), the standard \(\ln(x)\) function is reflected in the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm Domain
Understanding the domain of a natural logarithm function is crucial for graphing and solving problems involving logarithms. The natural logarithm, denoted as \(\ln(x)\), is defined only for positive values of \(x\). This means the input to the \(\ln\) function must be greater than zero (
\(x>0\)).

For the given function \(g(x) = \ln(-x)\), we must consider when \(\-x>0\), which translates to all the values for which \(x<0\). Consequently, the domain of \(g(x)\) is the set of all negative real numbers. In simpler terms, you can only plug negative numbers into \(g(x)\) to get a real result. It's important to remember that natural logarithms do not accept zero or negative numbers as inputs, which aligns with the logarithmic property that the argument must be positive.
X-Intercept Calculation
The \(x\)-intercept of a function is the point at which the graph of the function crosses the \(x\)-axis. To find the \(x\)-intercept, we set the function equal to zero and solve for \(x\).

For \(g(x) = \ln(-x)\), we calculate the \(x\)-intercept by solving \(\ln(-x) = 0\). Since the exponential form of the natural logarithm has base \(e\), we express this equation as \(e^{\ln(-x)} = e^0\), which simplifies to \(\-x = 1\). By multiplying both sides by \(\-1\), we find that the \(x\)-intercept is \(x = -1\). This tells us that the graph of our function touches the \(x\)-axis exactly at the point \(\-1, 0\). Knowing the \(x\)-intercept is useful not only for graphing but also for understanding the behavior of the function in relation to the \(x\)-axis.
Vertical Asymptote
A vertical asymptote is a line that the graph of a function approaches but never actually touches or crosses. It occurs at values of \(x\) where the function becomes undefined or approaches infinity.

For logarithmic functions, such as \(g(x) = \ln(-x)\), the vertical asymptote occurs where the argument of the logarithm is zero since the logarithm of zero is undefined. In our exercise, the argument \(\-x\) becomes zero when \(x = 0\). Therefore, the vertical asymptote for the function is the line \(x = 0\). This is a critical feature of the graph representing an 'invisible barrier' that the function values get infinitely close to but cannot cross. When graphing \(g(x)\), remember that the graph will approach this vertical asymptote from the left side, as the domain consists of negative \(x\)-values only.
Graphing Logarithmic Functions
Graphing logarithmic functions like \(g(x) = \ln(-x)\) involves understanding the function's domain, \(x\)-intercept, and asymptotes. The domain informs us which \(x\)-values are allowed, the \(x\)-intercept indicates where the graph intersects the \(x\)-axis, and the vertical asymptote shows where the function tends toward negative or positive infinity.

When graphing \(g(x)\), start by plotting the \(x\)-intercept, which we've determined to be \(x = -1\). Next, draw the vertical asymptote as a dashed line along the \(x = 0\) line. Since the function's domain is \(x<0\), we'll only sketch the graph on the left side of the \(y\)-axis. The curve approaches the \(x\)-axis near the \(x\)-intercept and then sweeps downward, getting closer and closer to the vertical asymptote without crossing it.

It's worth noting that \(g(x) = \ln(-x)\) is a reflection of \(\ln(x)\) across the \(y\)-axis due to the negative sign within the logarithm. This reflection results in a graph that decays towards the left, or negative side of the graph, illustrating that mathematical transformations can significantly change the function's graphical representation.

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