Chapter 0: Problem 70
Simplify each complex rational expression. $$\frac{\frac{6}{x^{2}+2 x-15}-\frac{1}{x-3}}{\frac{1}{x+5}+1}$$
Short Answer
Expert verified
The simplified form of the given complex rational expression is \(\frac{3}{(x-3)(x+6)}\).
Step by step solution
01
Simplify the Numerator
First, look at the numerator: \(\frac{6}{x^{2}+2 x-15} - \frac{1}{x-3}\). Notice that the denominator of the first part of the numerator (\(x^{2}+2 x-15\)) can be factored into \((x-3)(x+5)\). So the numerator can be rewritten as: \(\frac{6}{(x-3)(x+5)} - \frac{1}{x-3}\). To subtract these two fractions, let's first find a common denominator. Here, it is \((x-3)(x+5)\). After making the denominators the same, the simplified numerator becomes: \(\frac{6-(x-3)}{(x-3)(x+5)} = \frac{3}{(x-3)(x+5)}\)
02
Simplify the Denominator
Looking at the denominator: \(\frac{1}{x+5}+1\). We notice that it can be written in terms of a common denominator, \(x+5\), giving: \(\frac{1+(x+5)}{x+5} = \frac{x+6}{x+5}\)
03
Simplify the Complex Fraction
Now, replace your simplifications back into the original complex fraction to simplify further: \(\frac{(Numerator)}{(Denominator)} = \frac{(\frac{3}{(x-3)(x+5)})}{(\frac{x+6}{x+5})}\). Multiply by the reciprocal of the denominator to solve \(= \frac{3}{(x-3)(x+5)} *\frac{x+5}{x+6} = \frac{3}{x-3}*\frac{1}{x+6}\) after canceling out the common factor, \(x+5\).
04
Final Simplification
Finally, we have: \(\frac{3}{x-3}*\frac{1}{x+6} =\frac{3}{(x-3)(x+6)}\). This is the simplified form of the complex rational expression.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Polynomials
Factoring polynomials is like unlocking the hidden structure within a polynomial expression. When you factor a polynomial, you essentially break it down into smaller, simpler expressions called factors, which, when multiplied together, give you the original polynomial. In the exercise given, we encounter the polynomial \(x^2 + 2x - 15\). To factor it, look for two numbers that multiply to give the constant term \(-15\) and add up to give the middle coefficient \(2\).
- These numbers are \(-3\) and \(5\).
- Thus, the polynomial can be expressed as \((x - 3)(x + 5)\).
Common Denominator
Finding a common denominator is a key step when working with fractions, especially when you need to add or subtract them. It’s like finding a common language that both parts of a fraction can "understand." In order to simplify the given complex rational expression, it's essential to align the denominators of the fractions involved.
- In the numerator, we have: \(\frac{6}{(x-3)(x+5)} - \frac{1}{x-3}\).
- The least common denominator (LCD) here is \((x-3)(x+5)\) because it's the smallest expression that includes each denominator.
Fraction Simplification
Fraction simplification is about shrinking fractions into their simplest form. For complex rational expressions, it means boiling down a compound fraction into a straightforward fraction. Think of it as reducing clutter. You begin by combining or canceling out common elements in both the numerator and the denominator.
- After finding a common denominator, the new numerator becomes \(\frac{3}{(x-3)(x+5)}\).
- In the whole expression, the denominator simplifies to \(\frac{x+6}{x+5}\).
Reciprocal Multiplication
Reciprocal multiplication comes into play when you have to divide by a fraction. Instead of dividing, you multiply by the reciprocal. This method is a powerful trick to simplify complex rational expressions. In the given problem, after obtaining a reduced form of both the numerator and the denominator, we see:
- The problem boils down to \(\frac{(\frac{3}{(x-3)(x+5)})}{(\frac{x+6}{x+5})}\).
- Instead of directly dividing, you multiply: \(\frac{3}{(x-3)(x+5)} \times \frac{x+5}{x+6}\).