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Factor the numerator and the denominator. Then simplify by dividing out the common factor in the numerator and the denominator. $$\frac{x^{2}+6 x+5}{x^{2}-25}$$

Short Answer

Expert verified
\(\frac{x+1}{x-5}\)

Step by step solution

01

Factor the Numerator

Factor the expression in the numerator \(x^{2}+6x+5\). The factors of 5 that would add up to 6 are 5 and 1. So, \(x^{2}+6x+5\) is factored as \((x+5)(x+1)\).
02

Factor the Denominator

Factor the expression in the denominator \(x^{2}-25\). The expression is a difference of two squares, which can be factored into the product of the sum and difference of the square roots of both terms. Therefore, \(x^{2}-25\) is factored as \((x+5)(x-5)\).
03

Simplify the Rational Expression

Divide out the common factors in the numerator and the denominator. In this case, \((x+5)\) is a common factor. So, \(\frac{(x+5)(x+1)}{(x+5)(x-5)}\) simplifies to \(\frac{x+1}{x-5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Polynomials
Understanding how to manipulate polynomials is crucial in simplifying rational expressions. Factoring polynomials involves expressing a polynomial as a product of its factors. This can be quite similar to breaking down a number into its prime factors. For example, the polynomial x^2 + 6x + 5 can be factored by finding two numbers that multiply to give the constant term (5, in this case) and add up to the coefficient of x, which is 6.

The factors that satisfy these conditions are 5 and 1, and so, the polynomial x^2 + 6x + 5 is factored as (x + 5)(x + 1). It's like solving a mini-puzzle where you work backwards from the expanded form to its constituent multiplicative pieces. The ease of this process can vary depending on the complexity of the polynomial. Some polynomials may not factor into real numbers, reflecting the diversity of these mathematical expressions.
Difference of Two Squares
The difference of two squares is a specific type of factoring that students encounter often. It represents an expression of the form a^2 - b^2, which can be factored into (a + b)(a - b). This pattern emerges because when you expand (a + b)(a - b), the middle terms ab and -ab cancel each other out, leaving you with the difference between the square terms.

In the provided exercise, x^2 - 25 is a classic example of a difference of two squares, where a = x and b = 5. Factoring it gives us (x + 5)(x - 5). Recognizing this pattern is like seeing the hidden structure in a building—it lets you disassemble and reassemble expressions with ease, which is a handy skill in algebra.
Common Factors
Identifying common factors in the numerator and denominator of a rational expression is the last step to simplifying it. Common factors are expressions that appear in both the numerator and the denominator. Simplifying the rational expression means reducing it to its lowest terms by dividing out these common factors.

Imagine you have a fraction with 5 in both the top and bottom—you could simplify this to 1, as dividing by a common number does not change the value of the fraction. Similarly, in our exercise, the common factor of (x + 5) in both the numerator and the denominator can be divided out, leaving us with the simplified expression (x + 1)/(x - 5). It's essential to remember that a common factor can only be canceled if it is multiplied by the rest of the terms, not if it's added or subtracted.

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Most popular questions from this chapter

Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. A city commission has proposed two tax bills. The first bill requires that a homeowner pay \(\$ 1800\) plus \(3 \%\) of the assessed home value in taxes. The second bill requires taxes of \(\$ 200\) plus \(8 \%\) of the assessed home value. What price range of home assessment would make the first bill a better deal?

Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. On two examinations, you have grades of 86 and \(88 .\) There is an optional final examination, which counts as one grade. You decide to take the final in order to get a course grade of \(\mathrm{A},\) meaning a final average of at least 90 a. What must you get on the final to earn an A in the course? b. By taking the final, if you do poorly, you might risk the B that you have in the course based on the first two exam grades. If your final average is less than \(80,\) you will lose your \(\mathrm{B}\) in the course. Describe the grades on the final that will cause this to happen.

Solve each equation. $$\frac{x-1}{x-2}+\frac{x}{x-3}=\frac{1}{x^{2}-5 x+6}$$

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\frac{\sqrt{20}}{8}=\frac{\sqrt{10}}{4}$$

In solving \(\sqrt{2 x-1}+2=x,\) why is it a good idea to isolate the radical term? What if we don't do this and simply square each side? Describe what happens.

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